I am working on this problem and have been getting wrong answers I am not sure if it is due to integration or not but what I have so far determined is that. Note y1 = y1(x) and y2 = y2(x)distance to dm (r)=xDifferential Area (dA) = (y1 - y2) * dxDifferential Mass (dm) = sigma * (y1-y2) * dxDifferential Moment (dI) = x^2 * sigma(y1-y2)dx You are designing a part for a piece of machinery. The part consists of a piece of sheet metal cut as shown below. The shape of the upper edge of thepart is given by Yı(x), and the shape of the lower edge of the part is given by y2(x).Y1 (T) = h(4)*Y2(x) = h(4)*where h = 6.3 m and d = 3.2 my,(x)hYou decide to find the moment of inertia of the part about that y axis first. The mass density per area for the sheet metal is 3.2 kg/m^2. In order to findthe moment of inertia, first you must chop the part into small mass elements, dm's, that you know the moments of inertia for, dl's. Then you must usean integral to sum up all of the dl's. Moment of Inertia (y)Now find the total moment of inertia by adding up (integrating) all of the dl's. To do this, put everything in terms of x and compute the integralover x. Don't forget about limits. Then plug in the values for your constants so that you can get a value for the moment of inertia.Enter the numerical value for your I, below.A Hint About the Limits of IntegrationA Hint About Your IntegralI, = -4894.05378125%3DBoth y1 and y2 are functions of x. So you need to plug in the actual functions for y1 and y2 before you integrate!Your equation for dl is with respect to dx. So what axis should your bounds of integration be along? Then look at the points you areintegrating from to determine your limits.

Answered: Image /qna-images/answer/45aa0de7-2395-4f43-b70e-3bbacffc9049.jpg

Moment of Inertia (y) Now find the total moment of inertia by adding up (integrating) all of the dl's. To do this, put everything in terms of x and compute the integral over x. Don't forget about limits. Then plug in the values for your constants so that you can get a value for the moment of inertia. Enter the numerical value for your I, below. A Hint About the Limits of Integration A Hint About Your Integral = "I -4894.05378125 Both y1 and y2 are functions of x. So you need to plug in the actual functions for y1 and y2 before you integrate! Your equation for dl is with respect to dx. So what axis should your bounds of integration be along? Then look at the points you are integrating from to determine your limits.

Moment of Inertia (y) Now find the total moment of inertia by adding up (integrating) all of the dl's. To do this, put everything in terms of x and compute the integral over x. Don't forget about limits. Then plug in the values for your constants so that you can get a value for the moment of inertia. Enter the numerical value for your I, below. A Hint About the Limits of Integration A Hint About Your Integral = "I -4894.05378125 Both y1 and y2 are functions of x. So you need to plug in the actual functions for y1 and y2 before you integrate! Your equation for dl is with respect to dx. So what axis should your bounds of integration be along? Then look at the points you are integrating from to determine your limits.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 6P: Figure P1.6 shows a frustum of a cone. Match each of the three expressions (a) (r1 + r2)[h2 + (r2 ...

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