My Arrays.sort is not printing out sorted array ints. It prints out an unsorted list.
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My Arrays.sort is not printing out sorted array ints. It prints out an unsorted list.
package filterSort;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Arrays;
import java.util.Scanner;
import java.util.*;
public class FilterSort {
public static int[] doubleArrayAndCopy(int[] arr) {
int len = arr.length;
int max = arr.length * 2;
int[] copyArr = Arrays.copyOf(arr,max);
int length = copyArr.length-1;
Arrays.sort(copyArr, 0, length);
return copyArr;
}
public static void main(String[] args) {
int[] data = new int[8];
try {
File file = new File("data.txt");
Scanner myReader = new Scanner(file);
for(int i = 0; myReader.hasNext(); i++) {
if(i == data.length - 1) {
data = doubleArrayAndCopy(data);
}else {
if(myReader.hasNextInt()) {
data[i] = myReader.nextInt();
System.out.println(data[i]);
}else {
myReader.next();
}
}
}
} catch (FileNotFoundException e) {
System.out.println("File not found");
}
}
}
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- Write a program in java that randomly fills in 0s and 1s into an n-by-n matrix, prints the matrix, and finds the rows and columns with the most 1s. (Hint: Use two ArrayLists to store the row and column indices with the most 1s.)Fix the following method printEvenIndex so that it will print out the Integers at even indices of the passed-in ArrayList list. import java.util.*; public class Test1 { public static void printEvenIndex(ArrayList<Integer> list) { for (int i) { if (i % 2 == 1) { System.out.print(list.get(i) + ", "); } } } public static void main(String[] args) { //instantiate ArrayList and fill with Integers ArrayList<Integer> values = new ArrayList<Integer>(); int[] nums = {1, 5, 7, 9, -2, 3, 2}; for (int i = 0; i < nums.length; i ++) { values.add(nums[i]); } System.out.println("Expected Result:\t 1, 7, -2, 2,"); System.out.print("Your Result:\t\t "); printEvenIndex(values); } }Write a method quicksort that takes in an ArrayList of integers and returns them in ascending order, using a quicksort style of sorting. Remember that this style relies on choosing a pivot integer and breaking the set into values less than the pivot and more than the pivot, then repeating this process on each half until only single values are left, which are then put back together. public ArrayList<Integer> quickSort(ArrayList<Integer> list) { *code here*}
- Java Implement 5 methods given below in MyStringArrayList class // Add a new element, e, at the beginning of this list public void addFront(String e){ } //search for element e, returns true if found, otherwise returns false. public boolean contains(String e){ } //return the element at position i, otherwise returns null public String getElement(int i){ } // remove the element at specified index, returns the element that is being removed. Returns null if specified index is invalid. public String removeElementAt(int i){ } //returns a String representation of this list. public String toString(){ }java In this assignment you will swap a position in an array list with another. swap() gets 3 arguments, an Arraylist, a position, and another position to swap with. Example swap(["one","two","three"],0,2) returns:["three","two","one"] public static ArrayList<String> swap(ArrayList<String> list,int pos1,int pos2) public static void main(String[] args) { Scanner in = new Scanner(System.in); int size = in.nextInt(); int pos1 = in.nextInt(); int pos2 = in.nextInt(); ArrayList<String> list = new ArrayList<>(); for(int i=0; i < size; i++) { list.add(in.next()); } System.out.println(swap(list, pos1, pos2)); } }The split method in the String class returns an array of strings consisting of the substrings split by the delimiters. However, the delimiters are not returned. Implement the following new method that returns an array of strings consisting of the substrings split by the matching delimiters, including the matching delimiters. public static String[] split(String s, String regex) For example, split("ab#12#453", "#") returns ab, #, 12, #, and 453 in an array of String and split("a?b?gf#e", "[?#]") returns a, ?, b, ?, gf, #, and e in an array of String.
- Convert this Student Array code into Student Singly LinkedList using java. public class Student {static int index=0; int sid;String name;String date;char attendence;static Student[] stdarry=new Student[10];public void insert(int id, String nm, String dt, char att){stdarry[index]=new Student();stdarry[index].sid=id;stdarry[index].name=nm;stdarry[index].date=dt;stdarry[index].attendence=att;index++; }public int search(int id){int check=0;for(int i=0 ;i<index; i++){if(stdarry[i].sid==id){check=i;break;}}return check;}public void display(){ for(int i=0 ;i<index;i++){System.out.println("ID ="+stdarry[i].sid+"| Name ="+stdarry[i].name+"| Date ="+stdarry[i].date+"| Attendence ="+stdarry[i].attendence); }}public void UpdateAttendence( int id, String dt, char att){for(int i=0; i<index ;i++){if(stdarry[i].sid==id && stdarry[i].date==dt){stdarry[i].attendence=att;break;}}}public void showPresentStudent(String dt, char status) {int count = 0;System.out.println("Present Student…(IN JAVA) Implement a mergeUniqueValues(arr1, arr2) method. When passed two arrays of strings, it will return an array containing the strings that appear in either or both arrays in sorted order. And the returned array should have no duplicates. For example, if you have two string arrays: arr1: {“Bear”, “Elephant”,”Fox”}arr2: {“Panda”, “Elephant”,”Eagle”} Calling mergeUniqueValues(arr1, arr2) should return a merged and sorted array like: Bear, Eagle, Elephant, Fox, Pandawrite a java program that implements the bubble sort algorithum that sorts list of doubles in the range of [0,500). use array objects that use to contain the list