На Br The proton NMR would have total unique proton(s) in the spectrum. The carbon NMR would have total unique carbon(s) in the spectrum Ha would have the following multiplicity: Ha would have different J values. roton nmr choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 or more arbon nmr choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 or more a multiplicity choices: Singlet, doublet, triplet, quartet, quintet, doublet of doublets, doublet of triplets, triplet of triplets, publet of quartet

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter17: Alcohols And Phenols
Section17.11: Spectroscopy Of Alcohols And Phenols
Problem 19P: When the 1HNMR spectrum of an alcohol is run in dimethylsulfoxide (DMSO) solvent rather than in...
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For the compound below, answer the following questions:
На
Br
The proton NMR would have
• total unique proton(s) in the spectrum.
The carbon NMR would have
total unique carbon(s) in the spectrum.
Ha would have the following multiplicity:
Ha would have
different J values.
proton nmr choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 or more
carbon nmr choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 or more
ha multiplicity choices: Singlet, doublet, triplet, quartet, quintet, doublet of doublets, doublet of triplets, triplet of triplets,
doublet of quartet
ha j value choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 or more
Transcribed Image Text:For the compound below, answer the following questions: На Br The proton NMR would have • total unique proton(s) in the spectrum. The carbon NMR would have total unique carbon(s) in the spectrum. Ha would have the following multiplicity: Ha would have different J values. proton nmr choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 or more carbon nmr choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 or more ha multiplicity choices: Singlet, doublet, triplet, quartet, quintet, doublet of doublets, doublet of triplets, triplet of triplets, doublet of quartet ha j value choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 or more
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