Principles of Heredity 667 Activity 1 Working Out Crosses Involving Dominant and Recessive Genes For each of the following crosses, draw your own Punnett square and use the technique outlined above to determine the genotypes and phenotypes of the pea plant offspring 2. Genotypes of parents: Tt (3) × Tt (Q) % of each genotype: 1. Genotypes of parents: Tt (3) × tt (9) % of each phenotype: % tall, % dwarf % of each genotype: 3. Genotypes of parents: TT (3) X Tt (2) % of each phenotype: % tall, % dwarf % of each genotype: % of each phenotype: % tall, % dwarf Incomplete Dominance uhot alleles exnress themselves in the offspring. The crosses are

Principles of Heredity 667 Activity 1 Working Out Crosses Involving Dominant and Recessive Genes For each of the following crosses, draw your own Punnett square and use the technique outlined above to determine the genotypes and phenotypes of the pea plant offspring 2. Genotypes of parents: Tt (3) × Tt (Q) % of each genotype: 1. Genotypes of parents: Tt (3) × tt (9) % of each phenotype: % tall, % dwarf % of each genotype: 3. Genotypes of parents: TT (3) X Tt (2) % of each phenotype: % tall, % dwarf % of each genotype: % of each phenotype: % tall, % dwarf Incomplete Dominance uhot alleles exnress themselves in the offspring. The crosses are

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Description: Principles of Heredity667Activity 1Working Out Crosses Involving Dominant and Recessive GenesFor each of the following crosses, draw your own Punnettsquare and use the technique outlined above to determine thegenotypes and phenotypes of the pea plan

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter3: Transmission Of Genes From Generation To Generation

Section: Chapter Questions

Problem 16QP: More Crosses with Pea Plants: The Principle of Independent Assortment Consider the following cross...

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More Crosses with Pea Plants: The Principle of Independent Assortment Determine the possible genotypes of the following parents by analyzing the phenotypes of their children. In this case, we will assume that brown eyes (B) is dominant to blue (b) and that right-handedness (R) is dominant to left-handedness (r). a. Parents: brown eyes, right-handed brown eyes, right-handed Offspring: 3/4 brown eyes, right-handed 1/4 blue eyes, right-handed b. Parents: brown eyes, right-handed blue eyes, right-handed Offspring: 6/16 blue eyes, right-handed 2/16 blue eyes, left-handed 6/16 brown eyes, right-handed 2/16 brown eyes, left-handed c. Parents: brown eyes, right-handed blue eyes, left-handed Offspring: 1/4 brown eyes, right-handed 1/4 brown eyes, left-handed 1/4 blue eyes, right-handed 1/4 blue eyes, left-handed
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8. In guinea pigs, the allele for black fur (B) is dominant over the allele for white fur (b). Similarly, the allele for straight hair (H) is dominant over the allele for having rough hair (h). Pure breeding rough haired guinea pigs with black fur were crossed with pure breeding straight haired guinea pigs with white fur. a. State the genotype and the phenotype of the F1 individuals produced as a result of this cross.b. Two F1 offspring were mated together. Calculate the expected ratio of phenotypes in the F2 generation.c. Show the completed Punnett square below.