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Nanoparticle was synthesis from silver atoms with 1.8 nm of diameter. Find the ratio of the surface atoms of this particle.
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- Determine the volume of a rectangular prism with dimensions of 1.5x102 mm; 2.8x102 mm. and 3.3x102 mm2- While using organic solvent like chloroform (CHCl3) in the visible region measurements what cuvette material you would use? A) Glass B)Plastic C)Glass or Quartz D)Any of them E) Quartz.It is possible to synthesize a wide variety of materials with dimensions in the nanometer range. The transmission electron microscope (TEM) image shows gold nanoparticles (bright white) that have been coated with silica (SiO2 - not as bright). The scale bar in the lower right of the image corresponds to 40.0 nm. Assume that the gold nanoparticles are spherical and have a diameter of 10.0 nm. Answer the following questions. What is the volume of a single Au particle. What is the mass of the particle (look up the density for gold). If the initial solution that was used to synthesize the gold particles contained 50.0 mL of 1.00% (w/vol) Au, how many particles can you synthesize? If the diameter increases by 10%, what % change will occur in the number of particles made?
- Explain the difference between molecular mass and nominal mass. Give the value of the molecular mass and nominal mass of benzene, C6H6.Suppose you synthesized copper nanoparticles and found the average particle diameter to be 6.2 nm. How many copper atoms would you expect to find in the particle? One approach: assume the particle is spherical. In all cases, assume the particle has 24 Cu atoms across the diameter (the radius of each Cu atom is 128 pm) What fraction of the atoms would be surface atoms.2. What is the role of the fixer in black and white photography?
- Milk of magnesia with [H3O+] = 2.0 X 10-9MThe subatomic particle known as the proton has a mass of 1.67x10-24 g and a diameter of 1.00x10-13 cm. Calculate the density (in g/cm3) of an atom containing a single proton assuming a perfect spherical shape using the equation v = 4 3 π r 3The equation 250/ 96 Cm→?+ 98/38Sr +4 1/0 n is correctly completed as m 250Cm→ 148/59Ce + 98/38 Sr + 4 1/0n.