Give a clear explanation handwritten answer.... नी कोकटDज्ब्प कजप्ट nce +उच्unnon-QTGnवनीट लिमकाकार कैके० तल ककट कटकेकांडकलठड कीट Tवेवानीना की कैकट निमड् कल्त-क्वापाDocauज्प्छononceललटकेकांइललऐ केफए सीनड अटत - 5पनप्रा৪प? ज० ।, 4 - dीलाhong ben2ene.प - वालाला.०Tप benzene.

Tertiary carbocation is mose stable carbocation dye to hyper conjugation and +I effect .

जष्प क जप्छककnce +vuon oी क्रेतट 1- Q7Gmmdकीट लिमलnmर वीकने० लि किमट ललटकैवकांडन कैट बवेतीनीन्ता से कैरए ्रम्डक नलल - एवनंप्रा प ज० ।, ५-dालme-hoxg benzcne.

जष्प क जप्छककnce +vuon oी क्रेतट 1- Q7Gmmdकीट लिमलnmर वीकने० लि किमट ललटकैवकांडन कैट बवेतीनीन्ता से कैरए ्रम्डक नलल - एवनंप्रा प ज० ।, ५-dालme-hoxg benzcne.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Chemistry (i) For T = 298K ΔG° = -8.314 x 298 x ln (2.83x10-3) = 14.524 KJ/mol (ii) For T = 308.15K ΔG° = -8.314 x 308.15 x ln (9.619x10-3) = 11.891 KJ/mol (iii) For T = 318.15K ΔG° = -8.314 x 318.15 x ln (3.14x10-2) = 9.147 KJ/mol (iv) For T = 328.15K ΔG° = -8.314 x 328.15 x ln (8.82x10-2) = 6.621 KJ/mol (v) For T = 338.15K ΔG° = -8.314 x 338.15 x ln (2.42x10-1) = 3.990 KJ/mol Based on the measured ΔG° values, is this equilibrium spontaneous at room temperature? Which factor, entropy, or enthalpy, has the greater impact on spontaneity in this case? Explain your answers.
Use the following atomic masses (in g/mol): K = 39.1; Mn = 54.94; O = 16; H = 1; P = 30.97; C = 12.01; Na = 23; Mg = 24.31; S = 32.06; Zn = 65.38; Cu = 63.55 In the standardization of Hydrochloric Acid against pure anhydrous Sodium Carbonate, 1mL was found to be equivalent to 0.05g of the primary standard. Compute for the normality of the acid.
Q1: Write down the complete principle procedure apparatus of the saponification process?
Apply the Q test to the following data sets to determine whether the outlying result should be retained or rejected at the 95% confidence level. a. 85.10, 84.62, 84.70b. 85.10, 84.62, 84.65, 84.70
R=0.0526 kPa * km^-1 convert R to kJ * m^-4
Is ther an error in the solution that ∆Grxn=−9.33 kJ/mol=9330 J/mol was not kept negative when converted tfrom kJ to J? Can steps 3-5 be checked for accuracy ?
For the equation 2K + Cl2------>2KCl. I understand Cl is diatomic , but where does the 2 in front of the K come from.
Please solve using these equations: dCp/dt=-k(Cp) t1/2= 0.693/k Cp=C0e^-k(t)
Please use the following data to create a scatter graph with smooth lines and markers to connect and indicate the data points. X = Time (s) Y = Energy (kJ) 2 90 4 90 6 95 8 98 10 100 12 110 14 120 16 119 18 107 20 90 22 78 24 70 26 58 28 50 30 40 32 39 34 38 36 38 40 38
Assuming that the percent of uncertainty in the calculated molar mass is the same as the percent of uncertainty in the temperature change, calculate the uncertainty in the molar mass. Could the chemist unequivocally state that the substance is cocaine? For example, is the uncertainty small enough to distinguish cocaine from codeine (C18H21NO3, molar mass = 299.36 g/mol)?
What is the magnitude of the uncertainty introduced by the lack of knowledge of the specific heat sample
In order to avoid the possibility of 2-hour delays this winter, EKU will be stockpiling de-icing salts to help keep the roads and sidewalks clear. Facility Services has been quoted the following prices: K2SO4: $5.35/kg MgSO4: $4.55/kg Which salt provides a better value? Support your answer with a calculation.