Find the Fourier series for the given function. f(x) 9 200 f(x) ) = ²/²2 - ²2/2 2² 1 2m ² - 1 ² (2m - 1)лx L (m1)лx f(x) = 9 --> 100 9 -sin πm=1m - 1 L 9 (2m 1)лx f(x): - 20⁰ 9 · Σ πm=12m-1 -COS 2 L 9 200 9 ° f(x) = 2 + ²2₁ 22² sin((2m = 1) πm=12m - 1 L 9 2⁰0 9 (2m 1)лx f(x) (€ 2 πm=12m - 1 L = + - Σ - -sin -COS = f9, -L≤ x < 0, 0, 0 < x < L; f(x + 2L) = f(x)

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