Need help with question 3c. My work is also attached however I keep getting negative for my change.

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter15: Principles Of Chemical Reactivity: Equilibria
Section15.2: The Equilibrium Constant And Reaction Quotient
Problem 2CYU: Answer the following questions regarding the butane isobutane equilibrium (Kc = 2.50 at 298 K). (a)...
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Need help with question 3c. My work is also attached however I keep getting negative for my change.
For the equilibrium reaction CO) + H20(6) >CO2G) + H2G), the Keq value at
690°C is 10.0. A mixture of 0.300M of CO, 0.300M of H20,0.500M of CO2
and .500M of H2 is placed in a flask.
a. Show that the reaction is NOT at equilibrium (Trial Keq?)
b. Determine the direction in which the reaction will shift to reach
equilibrium
c. Calculate the equilibrium concentrations of all four species..
Corg)tH20q<>cOzig) + Hz(g
230OM
2000M :
+ Sc
SC
JC
E
Keq=
= IG.O
9)
=(0.300M)(.30OM)
(o.300M)(0.300M)
ミス。チQ<heyる
b) Shft to the left.
Transcribed Image Text:For the equilibrium reaction CO) + H20(6) >CO2G) + H2G), the Keq value at 690°C is 10.0. A mixture of 0.300M of CO, 0.300M of H20,0.500M of CO2 and .500M of H2 is placed in a flask. a. Show that the reaction is NOT at equilibrium (Trial Keq?) b. Determine the direction in which the reaction will shift to reach equilibrium c. Calculate the equilibrium concentrations of all four species.. Corg)tH20q<>cOzig) + Hz(g 230OM 2000M : + Sc SC JC E Keq= = IG.O 9) =(0.300M)(.30OM) (o.300M)(0.300M) ミス。チQ<heyる b) Shft to the left.
%3D
%3D
3.16
0.948+
-3人6x
-0.300M
O0448 =
-0.107t
%3D
-4.16
ー4.16
6.300MI)7
3.10-10.500-
5అంప క
0.300+5C
(0.300)(3.16)= Go948+3.1GJC = G0 S00-DC
G948+4.165= 0.500
- 0.948
- G.94 &
4.16 =
-Go448
4.16
4.16
%3D
Transcribed Image Text:%3D %3D 3.16 0.948+ -3人6x -0.300M O0448 = -0.107t %3D -4.16 ー4.16 6.300MI)7 3.10-10.500- 5అంప క 0.300+5C (0.300)(3.16)= Go948+3.1GJC = G0 S00-DC G948+4.165= 0.500 - 0.948 - G.94 & 4.16 = -Go448 4.16 4.16 %3D
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