Need help with the last question Not Secure - a5.chem.binghamton.edu CE LON-CAP.MC Kimetsu...M Mathway.G 25 ml to I..Chem 10...In the titration of 25.00 mL of a water sample, it took 19.090 mL of 3.165x 10-3 M EDTA solution to reach theendpoint.Calculate the number of moles of EDTA required to titrate the water sample. (enter your answer with 3 significantfigures)6.04x10-5You are correct.Your receipt no. is 151-9969 2Previous TriesThe total hardness is due to one or a combination of Ca2+, Mg²+, and Fe2+ in your sample. It is convenient to expressthis hardness as though it was entirely due to Ca²+. Making this assumption, determine the number of moles of Ca2+present in the bottled water sample titrated. (enter your answer with 3 significant figures)6.04x10-5You are correct.Your receipt no. is 151-1871 ?PreviousThe total hardness is always listed in parts-per-million (ppm) of CaCO3 (or mg CaCO3 / Kg H2O). Since the density ofwater is 1.0 g/mL, one ppm would be the same as the number of mg of CaCO3 per liter of water. Determine thenumber of moles of CaCO3 present in the titrated sample of water, assuming that all the Ca2+ combines with CO3²-.(enter your answer with 3 significant figures)6.04x10-5You are correct.Previous TriesYour receipt no. is 151-974 ?Calculate the number of grams of CaCO3 present and convert to mg. (enter your answer with 3 significant figures)6.05You are correct.Your receipt no. is 151-8327 ?Previous TriesConvert the number of mL of bottled water used in each sample titration to Liters. (enter your answer with 3 significantfigures)1,773FEB14étvMacBook Airesc000

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Need help with the last question

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter11: Dynamic Electrochemistry

Section: Chapter Questions

Problem 3P

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1.065g of MgO (Analyte) of 84.74% were treated w/ 50ml of 1.02N H2SO4 (Acidic Titrant), and 48.28 mL of NaOH (Base Titrant) 1.103N concentration MW of analyte: 40Meq of analyte: 0.02NaOH vol: 48.28 Compute for the meq weight consumed by the acidic titrant (g-meq)
1. 1093-g sample of impure Na2CO3 was analyzed by residual precipitimetry. After adding 50.00 mL of 0.06911 M AgNO3, the sample was back-titrated with 0.05781 M KSCN, requiring 27.36 mL to reach the endpoint. The percentage Na2CO3 (MW = 106.0 g/mole) in the tested sample is ________ % ? Note: Express final answer using least number of significant figures. 2. The alkalinity of natural waters is usually controlled by OH- (MW = 17.01 g/mole), CO3-2 (MW = 60.01 g/mole), and HCO3- (MW = 61.01 g/mole), which may be present singularly or in combination. Titrating a 10.0-mL sample to a phenolphthalein endpoint requires 38.12 mL of a 0.5812 M solution of HCl, and an additional 18.67 mL of the same titrant to reach the methyl orange endpoint. The composition of the sample is _________% CO3-2 and ___________ % OH- Note: Express final answers using least number of significant figures.
A solid containing tris was dissolved in water and brought to a total volume of 50.00 ml. A 10.00 ml aliquot of the solution was titrated with 0.09978 M HCl to a bromcresol green endpoint. The aliquot consumed 38.93 ml of titrant. Calculate the weight of tris in the original sample.
A 50 mL sample solution containing 8-hydroxyquinoline (MW: 145) was analyzed by adding 25 ml, 0.1 M KBrO3, excess KBr and acidified. The mixture was left for 10 minutes in dark place. After this time KI in excess was added followed by titration with 27.9 mL, 0.05 M thiosulfate standard solution. Write balance equations? What is the percent w/v 8-hydroxyquinoline in sample?
A 350.00 mL solution of 0.00265 M A3B4 is added to a 280.00 mL solution of 0.00205 M C3D2. What is pQsp for A3D4?
To a 0.5 g sample of impure NaCl are added 0.784 g of pure AgNO3 (MW = 169.88) crystal. This is in excess of the amount required to ppt. All the Cl as AgCl. After dissolving and filtering out the pptd. AgCl, the filtrate requires 25.50 ml of 0.28M KCNS. What is the percentage of NaCl (MW=58.44) in the sample?
A 20 ml aliquot of malonic acid solution was treated with 10.0 ml of 0.25M Ce4+ leading to the reaction CH2(COOH)2 + 6Ce4+ + 2H2O ® HCOOH + 2CO2 + 6Ce3+ + 6H+ After standing for 10 minutes at 60oC, the solution was cooled and the x’ss Ce4+ was titrated with 0.1M Fe2+, requiring 14.4 ml to reach the ferroin end point. Calculate the M of the malonic in the sample.
A 0.1093-g sample of impure Na2CO3 was analyzed by the Volhard method. After adding 50.00 mL of 0.06911 M AgNO3, the sample was back-titrated with 0.05781 M KSCN, requiring 27.36 mL to reach the endpoint. Report the purity of the Na2CO3 sample. [Ans. 90.9 % (w /w )]
The sulfate in 266.5 mg sample was precipitated as BaSO4 by addition of 27.00 mL of 0.0340 M BaCl2. The precipitate was removed by filtration and the remaining BaCl2 consumed 34.2 mL of 0.0200 M EDTA for titration to the end point. (All 1:1 ratio) Calculate the % SO3 in the sample. (MW of SO3 is 80.06 g/mol)
A solid sample containing chloride and with a mass equal to 6.000 g was dissolved in water and transferred to a 100.0 ml flask. A 50.0 mL aliquot of this solution was diluted to 250.0 mL. In the titration of 20.0 mL of the diluted solution, 32.0 mL of 0.2000 mol L-1 AgNO3 standard solution were used. Calculate the % of impurities in the analyzed sample. Data: Cl = 35.45
A 49.10 mL aliquot from a 0.500 L solution that contains 0.530 g of MnSO4 (MW=151.00 g/mol) required 41.6 mL of an EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCO3 ( MW=100.09 g/mol) will react with 1.53 mL of the EDTA solution?
Calcium fluoride is considered as a relatively insoluble compound and therefore lime or slakedlime has been considered as a possible material to remove excess fluoride in water of boreholesin certain parts of the country. The solubility product of CaF2 is Ksp = 3 x 10 – 11 and that ofCa(OH)2 isKsp =8x10-61. How much lime can be added to the water to remove 10 mg of F- ion per litre ofborehole water?(The atomic masses are Ca: 40.08; F: 19.00; O: 16; H: 1)