Newtons version of Kepler's third law is P2=4pi2/(G(M1+M2)) x a3. Since the square of the period P varies inversely with the Sum of the masses (M1+M2), the period itself depends on the inverse square root of the object masses. If a solar system has a star that is 3.9 times as massive as our Sun, and if that solar system has Earths exact twin, what is the orbital period of that planets months ?
Newtons version of Kepler's third law is P2=4pi2/(G(M1+M2)) x a3. Since the square of the period P varies inversely with the Sum of the masses (M1+M2), the period itself depends on the inverse square root of the object masses. If a solar system has a star that is 3.9 times as massive as our Sun, and if that solar system has Earths exact twin, what is the orbital period of that planets months ?
Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter2: Newtonian Mechanics-single Particle
Section: Chapter Questions
Problem 2.49P
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Newtons version of Kepler's third law is P2=4pi2/(G(M1+M2)) x a3. Since the square of the period P varies inversely with the Sum of the masses (M1+M2), the period itself depends on the inverse square root of the object masses. If a solar system has a star that is 3.9 times as massive as our Sun, and if that solar system has Earths exact twin, what is the orbital period of that planets months ?
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