Nitrogen dioxide dimerizes according to the following reaction: 2 NO2 (g) = N2O4 (g) K, = 6.7 at 298 K A 2.25-L container contains 0.059 mol of NO2 and 0.081 mol of N204 at 298 K.

Chemistry: Principles and Reactions
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Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 31QAP: A compound, X, decomposes at 131C according to the following equation: 2X(g)A(g)+3C(g)K=1.1103 If a...
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Is the reaction at equilibrium? If not, in what direction will the reaction proceed? 

Nitrogen dioxide dimerizes according to the following reaction:
2 NO2 (g) = N2O4 (g)
Kp = 6.7 at 298 K
A 2.25-L container contains 0.059 mol of NO2 and 0.081 mol of
N204 at 298 K.
Transcribed Image Text:Nitrogen dioxide dimerizes according to the following reaction: 2 NO2 (g) = N2O4 (g) Kp = 6.7 at 298 K A 2.25-L container contains 0.059 mol of NO2 and 0.081 mol of N204 at 298 K.
Expert Solution
Step 1

We have the following reation:2NO2gN2O4gGiven:KP=6.7 at 298KVoplume of the container=2.25LNo. of moles of NO2=0.059No. of moles of N2O4=0.081First we need to calculate the concentration of both the NO2 and the  N2O4 for this we apply the following formula,Concentration/molarity=no. of moles volume in litersTherefore,NO2=0.059 mol2.25 L                       N2O4=0.081 mol2.25 LNO2=0.026223M                       N2O4=0.036M       

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