Observe the following function. Note that the docstring states its intended behaviour. def alphabet_order (S1, s2): compares two strings with regard to their alphabetical ordering returns -1 if S1 comes before s2, 1 if 82 comes before s1, and 0 if they are identical s1 = s1.lower () s2 = s2.lower () for i in range (max (len (81), len(S2))): if s1[i] < s2[i]: return -1 elif s2 [i] < s1[i]: return 1 if len(S1) < len(S2): return -1 elif len (S2) < len (S1): return 1 return 0 This function contains a fault. Which of the following test cases would reveal the fault? Select one: O a. "Pikachu", "jolteon" O b. "snorlax", "snorlax" O c. "mew", "mewtwo" O d. "pikachu", "JOLTEON" O e. "pikachu", "flareon"

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Observe the following function. Note that the docstring states its intended behaviour.
def alphabet_order (S1, s2):
""" compares two strings with regard to their alphabetical ordering
returns -1 if s1 comes before s2, 1 if s2 comes before s1, and 0 if they are identical
si = s1.lower ()
s2 = s2.1ower ()
for i in range (max (len (S1), len (S2))) :
if s1[i] < s2 [i]:
return -1
elif s2 [i] < s1[i]:
return 1
if len (S1) < len (S2) :
return -1
elif len (S2)
< len (S1) :
return 1
return 0
This function contains a fault. Which of the following test cases would reveal the fault?
Select one:
O a. "Pikachu", "jolteon"
O b. "snorlax", "snorlax"
O c. "mew", "mewtwo"
O d. "pikachu", "JOLTEON"
O e. "pikachu", "flareon"
Transcribed Image Text:Observe the following function. Note that the docstring states its intended behaviour. def alphabet_order (S1, s2): """ compares two strings with regard to their alphabetical ordering returns -1 if s1 comes before s2, 1 if s2 comes before s1, and 0 if they are identical si = s1.lower () s2 = s2.1ower () for i in range (max (len (S1), len (S2))) : if s1[i] < s2 [i]: return -1 elif s2 [i] < s1[i]: return 1 if len (S1) < len (S2) : return -1 elif len (S2) < len (S1) : return 1 return 0 This function contains a fault. Which of the following test cases would reveal the fault? Select one: O a. "Pikachu", "jolteon" O b. "snorlax", "snorlax" O c. "mew", "mewtwo" O d. "pikachu", "JOLTEON" O e. "pikachu", "flareon"
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