of 7 Nm for an area of hole in mm?. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate: 4.1. Energy required to cut a hole. 4.2. Energy required for cutting work per second.

of 7 Nm for an area of hole in mm?. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate: 4.1. Energy required to cut a hole. 4.2. Energy required for cutting work per second.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: 22. Calculate the rpm for machining a cast iron work piece 10 inches in diameter and the cutting…

Q: In a surface broaching process, a broach having 5 mm pitch and cut per teeth 0.05 mm is used for…

Q: Calculate resultant force, metal removal rate and shear strain in an orthogonal cutting the depth of…

Q: Calculate the spindle speed for a Lathe Machine, if the cutting speed for a mild steel material…

A: Cutting speed for mild steel, Vc=34 m/min Diameter of workpiece, d=46 mm=0.046 m

Q: Calculate the r/min required for finish turning

Q: In an orthogonal cutting operation an 8 mm deep groove is to be turned on a 50 mm diameter steel…

Q: (b):- Calculate the total time to mill a block of aluminum with dimensions of 100 x 40 x 50 to…

Q: A pre-drilled hole of $10 mm in a block of 40 mm thick is required to be enlarged to 0 16mm by core…

A: we are supposed to answer only 3 sub parts..please post other parts as the other question. Given =…

Q: In Example 21.3, if the cutting speed V is doubled, will the answer be different? Explain.

A: Solution:

Q: Find the time required for one full cut on a work piece of 350mm long and 20 mm in diameter. The…

Q: Calculate the time required to make a ravage cut, at a feed rate of 0.015in. on a piece of machine…

A: Given:L=18 ind=2 infn=0.015 in/sec

Q: If a fairing operation is executed at a rotational speed of 40.0 rev / min, the feed is 0.015 in /…

A: As the outer and inner diameter is not given so I am assuming it as D0 and Direspectivelya)…

Q: length is 1100 mm. The feed is 0.35 mm/rev and the depth of cut is 2.5 mm. The cut will be made with…

A: Given data:-diameter of bar, D=400mmLength of bar, L=1100mmfeed, f=0.35mm/revdepth of cut,…

Q: Q4. A hole with 40 mm diameter an 50mm depth is to be drilled in mild steel component. The cutting…

Q: It is required to cut screw threads of 2 mm pitch on a lathe. The lead screw has a pitch of 6 mm. If…

A: Given:- Pitch of screw (P1) = 2 mm Pitch of lead screw (P2) = 6 mm Speed of spindle (N2 ) = 60 rpm…

Q: Calculate the machining time to complete the job as shown below from a bar 120 mm long and 60 mm…

A: Given: length of the job→L=120 mm initial diameter→D=60 mm maximum depth of cut→d=5 mm hence in…

Q: What is the main reason for this, and what is one drawback of increasing speed? Name 2 reasons why…

A: (A) Grinding spindles are manufactured to operate at higher and higher speed because: 1. At higher…

Q: Explain the mechanics of metal cutting with neat sketch. Why machining of ductile and brittle…

A: Draw a diagram showing the basic metal cutting process.

Q: In a turning operation, the workpiece diameter is Dm-40.00 mm and the diameter after the operation…

A: GIVEN DATA - D=40mm D2=24mm V=132m/min f=0.03mm/rev WE HAVE TO CALCULATE MRR

Q: *Using the Taylor equation for tool life and Tetting n = 0.5 and C= 400, calculate the percentage…

A: Given that, Tool exponent, n=0.5,Constant, C=400,Cutting speed is reduced by 50 %, Writing Taylor…

Q: In a cutting test with 0.3 mm flank wear as tool failure criterion, a tool life of 10 min was…

Q: A 12" x 4" block of soft aluminum alloy (u, = 2.5 hp.min/in³) is face milled at a depth of cut of…

A: Given Data: Depth of cut DC=18inch Length of block l=12 in Breadth of block b=4 in ut of aluminium…

Q: Example: A cylinder of 155 mm diameter is to be reduced to 150mm diameter in one turning cut with a…

Q: Example 3.18 A low carbon steel bar of 147 mm diameter with length of 630 mm is being turned with…

A: Given data as per the question A low carbon steel bar of 147 mm diameter with a length of 630 mm

Q: In a cutting test with 0.3 mm flank wear as tool failure criterion, a tool life of 10 min was…

A: Taylor's tool life equation is given by F.W. Taylor. Taylor's tool life equation gives the relation…

Q: “Milling is an intermitted cutting operation”. Explain it

A: Intermittent cutting is that cutting when the cutting is interrupted or we can say at some time tool…

Q: Example 4.2.5: Turning tool made of HSS used in the long process of turning shaft of aluminum alloy…

Q: Draw the geometry of single point cutting tool (3 views) and explain the importance of each angle in…

A: Draw the geometry of the section of the cutting tool perpendicular to the base and parallel to the…

Q: What is the cutting speed of a material with a radius of 40 mm and a speed of 1000 rpm?

Q: If shear strength is 6000 kg/cm2, width of cut is 10mm, cutting speed is 30 m/min, coefficient of…

A: Given:shear strength,ζ=6000 Kg/cm2 =6000*9.8110-4ζ=588.6 MPab=10 mmVelocity of cutting,V=30…

Q: Assume that, in orthogonal cutting, the rake angle, oz, is 20° and the friction angle, B, is 35° at…

A: Merchant theory gives higher shear plane angle means smaller shear plane and lower shear force which…

Q: 3. It is required to machine a slot with length 100 mm, width 15 mm, and depth 4 mm. Calculate the…

A: Given: The length of machine slot, L = 100 mm The width of machine slot, b = 15 mm The depth of…

Q: In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg…

Q: A hole of 40 mm diameter and 50 mm depth is to be drilled in a milled steel component. The cutting…

Q: Manufacturing Processes What is the effect of shear plane angle in metal cutting? Illustrate with…

A: What is the effect of shear plane angle in metal cutting? Illustrate with diagram

Q: A tool with zero rake angle used in orthogonal cutting when its clearance angle a is changed from 10…

A: Given:initial rake angle, α1=10ofinal rake angle, α2=7o

Q: In an orthogonal turning process, the chip thickness is 0.32 mm , feed is 0.2 mm/rev, then calculate…

A: Given data: The chip thickness is tc = 0.32 mm. The feed is f = 0.2 mm/rev.

Q: 5. AT-slot is to be cut in a C.I. slab 260 mm long as shown make the T-slot if the cutting speed is…

A: Given Cutting speed, v = 25 m/min Diameter, d = 20 mm Number of teeth, z = 6 Find…

Q: Calculate the r/min required for finish turning a 2in diameter piece of machine steel (The cutting…

A: Given :- Dia of piece, D=2 inch Cutting speed, V=100 inch/min

Q: 4- Explain why continuous chips are not necessarily desirable. 5- List the factors that contribute…

A: Given questions are related to manufacturing engineering 4. Explain why continuous chips are not…

Q: 2 1.63 With a carbide tool, the temperature in a cutting operation is measured as 650K when the…

A: Given: feed = 0.05 mm/rev T1=650 K

Q: f cut is 2 mm, what is the value of maximum uncut chip thickness when the table feed is 20 mm/min?

Q: What is the cutting ratio? Is it always less than 1?explain

A: Cutting ratio (r): Cutting ratio is defined as the ratio of thickness of metal before cutting that…

Q: 1. “Milling is an intermitted cutting operation”. Explain it.

A: Intermittent cutting means the cutting is not continuous. That means at some time the tool is in…

Q: b):- Calculate the total time to mill a block of aluminum with dimensions of 100 x 40 x 50 to remove…

Q: The cutting speed in in/min of a 12 mm drill operating at 600 rpm is nearly equal to

A: The cutting speed is 890.5 in/min.

Q: Problem 10.21 Estimate the time required for one complete cut on a workpiece of length 350 mm and…

Q: Calculate the machining time to drill four 20 mm diameter holes and one 50 mm diameter central'…

A: depth = 20 mm number of revolution required = depth / feed = 20/ 0.2 = 100 rev V = πDN100020 =…

Q: B/ In a drilling operation using a twist drill, the rotational frequency is 5 s', the feed rate is…

Concept explainers

Machining Processes and Machine Tools

Machining is represented as the process in which an excessive amount of substance is eliminated from the particular element in the form of pieces. In machining, cutting tools such as rotary tools, lathe, drill press, grinder, chop saw, welders, and many more are applied to get the desired shape. As compared to other manufacturing processes, machining is precise and versatile.

Question

100%

A motorised metal guillotine machine is required to cut 45 mm diameter hole in
a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque
of 7 Nm for an area of hole in mm?. If the cutting takes 1/10 of a second and
the speed of its flywheel varies from 165 rpm to 145 rpm, calculate:
4.1.
Energy required to cut a hole.
4.2.
Energy required for cutting work per second.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm2. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate:
A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm². If the cutting takes 1/10 of a second and the speed of it's flywheel varies from 165 rpm to 145 rpm, calculate 4.1)Energy required to cut a hole 4.2)Energy required for cutting work per second. 4.3)Maximum fluctuation of energy of the flywheel 4.4)Mass of the flywheel having radius of gyrations of 1,5 m
A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm2. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate:4.1. Energy required to cut a hole.4.2. Energy required for cutting work per second.4.3. Maximum fluctuation of energy of the flywheel.4.4. Mass of the flywheel having radius of gyration of 1.5 m.
A motorised metal guillotine machine is required to cut 45 mm diameter hole in a plate of 20 mm thickness at rate of 35 holes per minute. It requires a torque of 7 Nm for an area of hole in mm2. If the cutting takes 1/10 of a second and the speed of its flywheel varies from 165 rpm to 145 rpm, calculate: 4.1. Energy required to cut a hole. (4) 4.2. Energy required for cutting work per second. (2) 4.3. Maximum fluctuation of energy of the flywheel. (4) 4.4. Mass of the flywheel having radius of gyration of 1.5 m.
A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy= 1200 ksi. If the width of cut is 0.30 in. and the student set a rake angle of 0° and a cutting speed of 200 ft/ min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?
Suppose in a face milling operation, the dimensions of the workpiece are 5 inches by 10 inches. The cutter is 6 inches in diameter, has 8 teeth, and rotates at 300 rpm. The depth of cut is 0.125 inches and the feedrate is 0.005 inches / tooth. Assume that the specific power requirement for this material is 2 hp min / in3 and that only 75% of the cutter diameter is involved in cutting. Calculate (a) the required power, and (b) the material removal rate.
Find the machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by using a carbide insert. If the approach length and over run length is taken as 5 mm, Cutting speed as 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mm
A student is using a lathe with 80-hp and 80% efficiency to fabricate a copper alloy with Sy = 1200ksi If the width of cut is 0.30 inand the student set a rake angle of 0and a cutting speed of 200fl / min while she assumed a coefficient of friction to be 0.5. What is the maximum depth of cut the student can achieve?
Assuming that the coefficient of friction is 0.25, calculate the maximum depth of cut forturning a hard aluminium alloy on a 15-kW lathe (with a mechanical efficieny of 80%) at awidth of cut of 6 mm, rake angle of 0˚, and a cutting speed of 90 m/min, shear strength of 150 MPa.
A steel rod 250 mm long and 200 mm in diameter is being reduced to 190 mm in diameter all over its length in one travel. The machine spindle rotates at 500 rpm, whereas the tool is moving at an axial feed of 0.5 mm/rev; calculate the following: Material removal rate (mm3/min) Consumed gross power in Nm/s if cutting force is 477.5N and mechanical efficiency is 90% Cutting time plzz complete in 30 minutes
Calculate the spindle speed for a Lathe Machine, if the cutting speed for a mild steel material workpiece is 34 m/min and the diameter of the cylindrical workpiece is 46 mm.
Find the machining time, in seconds, and the rate of material removing in mmA3;sec for a turning operation having the following information: 1- Wp diameter is 80mm, 2- the length is 0.12m, 3- the cutting speed is 80m/min, 4- feed i50.5 mm/rev and 5- the depth of cut is 0.002m.