OH 1. Na OEt CH3OH Br Br2 HBr ÓCH, d = Radical chain addition e = Electrophilic addition a = Proton transfer g= E2 Elimination h = SN1 Nucleophilic substitution i = SN2 Nucleophilic substitution b= Lewis acid/base c = Radical chain substitution f= El Elimination Identify the mechanism by which each of the reactions above proceeds from among the mechanisms listed. Use the letters a - i for your answers. 1. 2. 2.
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- Decide which compounds from the list below are best suited for nucleophilic addition reactions and which ones are more appropriate for nucleophilic substitution reactions.1. Write in the product of 1-Fluoro-3,7-dimethyl oct-4-yne with these reagents a) ---excess H2,Pd/C----> b) ---Na, NH3------------> c) ---H2, Lindlar catalyst-->What are the characteristics of the a good nucleophile for SN2? How does a chemist tell a strong versus weak or bulky versus not bulky nucleophile? What is the best type of solvent for this reaction? Please define the terms. Thank you.
- Below is the equation for a nucleophilic substitution reaction and some experimental data. CH3CH2Br + CH3COO- ⇌ CH3CH2CO2CH3 + Br- ΔH=-75 kJ/mol Rate = k [CH3CH2Br][CH3COO-] Which reaction energy profile would be the best representative of the data provided?I’m currently trying to write a lab report for the synthesis of dimolybdenum tetraacetate [Mo2(O2CCH3)4] from the reaction of molybdenum hexacarbonyl, Mo(CO)6 in glacial acetic acid and acetic anhydride under a nitrogen atmosphere, involving the difficult formation of a quadruple bond and requires high heat and long reaction time (approximately 20 hours). But these are the question I’m stumped on: 1. Why need the reaction be done under nitrogen? We also added dichlorobenzene and hexanes during the reaction. 2. Explain the purpose of dichlorobenzene and hexanes. 3. Why does the reaction take 20 hrs?Below is the equation for a nucleophilic substitution reaction and some experimental data. CH3CH2Br + CH3COO- ⇌ CH3CH2CO2CH3 + Br- Rate = k [CH3CH2Br][CH3COO-] Which mechanism would best fit the data?
- In SN2 reactions of haloalkanes, the order of reactivity is RI>RBr>RCl>RF. Alkyl iodides are considerably more reactive than alkyl fluorides, often by factors as great as 106. All 1-halo-2,4-dinitrobenzenes, however, react at approximately the same rate in nucleophilic aromatic substitutions. Account for this difference in relative reactivities.Part 1 regards the images.Part 2: Identify the 4 unique common elementary steps in the above mechanism. (Electrophilic addition, Carbocation rearrangement, Bimolecular nucleophilic substitution (SN2), Nucleophilic addition, Nucleophile elimination, Bimolecular elimination (E2), Coordination, Proton transfer, Electrophile elimination, Heterolysis).Part 3: Fill in the blank: Both E1 and E2 produce the ___ alkene.For SN2 Explain the order in which 1o (primary) alkyl halides reacted and explain why. The 1o primary alkyl halides are: (see picture below) 1-chlorobutane 1-bromobutane 1-chloro-2butene benzylchloride
- 1. Write down all the steps of the reaction of 2-Methyl-2-hexene with sulfuric acid and name the product formed. Will provide helpful ratings for correct solution.Phineas and Ferbs, two brothers who enjoy vacations, doing fun things every summer. This summer the brothers and their friends carry out an organic synthesis with an unknown compound (L1) that contains 52% Carbon, 6% Hydrogen and 42% bromine, this compound (L1) is treated with magnesium in ether to obtain L2 , which reacts violently with D2O for 1-methyl cyclohexene with a deuterium atom in the methyl group (L3). The L2 reaction is treated with acetone followed by hydrolysis to give L4. Heating L4 with concentrated sulfuric acid gives L5, which decolors the bromine, obtaining L6. L5 undergoes hydrogenation with excess hydrogen and platinum as a catalyst giving rise to isobutyl cyclohexane. Determine the structures of compounds L1 through L6.1. i.What are the various ways by which alkenes may be synthesized? ii. Give two examples each of Unsymmetrical alkenes and reagents. iii. Give two examples of reactions of alkenes that result in Anti-Markonikov’s addition products