Question 6: Draw the organic products formed when each alkyne is treated with two equivalents of HBr. a. CH₂CH₂CH₂CH₂-C=C-H b. CH3-C=C-CH₂CH3 C. C=CH

Organic Chemistry
9th Edition
ISBN:9781305080485
Author:John E. McMurry
Publisher:John E. McMurry
Chapter9: Alkynes: An Introduction To Organic Synthesis
Section9.SE: Something Extra
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Question 6
Question 5: Draw the products of the following reaction, including
stereochemistry.
CH3C-CH
a. CH₂CH₂CH₂CH₂-C=C-H
H
a) Br₂ +
b) Cl₂ +
CH3
trans-2-butene
Question 6: Draw the organic products formed when each alkyne is treated with
two equivalents of HBr.
CH₂CH₂C=CCH₂CH3
CH₂CH₂C=CCH₂CH3
Br₂
H₂O
b. CH3-C=C-CH₂CH₂
Question 7: Draw the products formed when 3-hexyne is treated with each
reagent: (a) Br2 (2 equiv); (b) Cl2 (1 equiv).
→ ????
⇒ ????
C.
-C=CH
Transcribed Image Text:Question 5: Draw the products of the following reaction, including stereochemistry. CH3C-CH a. CH₂CH₂CH₂CH₂-C=C-H H a) Br₂ + b) Cl₂ + CH3 trans-2-butene Question 6: Draw the organic products formed when each alkyne is treated with two equivalents of HBr. CH₂CH₂C=CCH₂CH3 CH₂CH₂C=CCH₂CH3 Br₂ H₂O b. CH3-C=C-CH₂CH₂ Question 7: Draw the products formed when 3-hexyne is treated with each reagent: (a) Br2 (2 equiv); (b) Cl2 (1 equiv). → ???? ⇒ ???? C. -C=CH
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On 6b, why are the two Br on the 2nd carbon and not the 3rd??

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