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- 3. a. Briefly explain why internal standardization method is useful inanalytical chemistry?b. Why does a response factor of an instrument’s detector need to becalculated?Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any âdriftâ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…FT-IR technique can be utilized for the analysis of unknown analytes by matching it with__________. Both choices are correct Commercial library/database Reference standard
- Show all steps leading to the final answer po. Here’s a pdf file in accordance with the topic po: https://drive.google.com/file/d/1_FnDtXCrFKSol3RNWIG_9tNQ7IxgxD6t/view?usp=drivesdkIf 5 µM enzyme was used to obtain the data in the summary plot below, V-max = ________________ µM sec-1 and Km = ____________ µM for this enzyme (Enter numeric values to the nearest integer; Do NOT write units.)Which statements are TRUE regarding internal standards? I. The response factor is calculated by using a mixture containing known amounts of analyte and internal standard and by using detector response to the analyte and the internal standard. II. Internal standards are useful where instrument response or quantity of sample analyzed varies over time. III. Detector response is inversely proportional to concentration. IV. Detector response to analyte and internal standard is assumed to be constant over a range of concentrations A. I, II, and III B. II, III, and IV C. I and II D. I, II, and IV
- Please answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466Explain why internal standard can be used for ICP-OES but is not used for AASModule Code & Title: CHM9011M Chromatography and Sep Sciences Section 1: Purpose Clarity of Purpose ): Clearly states the purpose of the SOP. Relevance to Task : Demonstrates the importance and relevance of the procedure. Alignment with Goals ): Shows how the procedure aligns with organisational goals.
- Help with q=mcchange in temp ?The velocity selector in the problem prior to this one is used in a mass spectrometer. Protons(with zero neutrons) are the most common hydrogen nuclei. Some hydrogen isotopes, however, haveeither one or two neutrons in addition to the proton. If a beam of hydrogen nuclei is shot into amagnetic eld of strength 2.0T and the nuclei do a u-turn after which they strike a detector, how farapart will the three isotopes be on the detector surface? Assume both protons and neutrons have amass of 1:67 10?27kg and e = 1:60 10?19C.Cont.Instrumental studies involve the calculation of the instruments' limit of detection (LOD) in addition to the calibration curve. a. What exactly is LOD? b. Why is it necessary to determine it? c. Hpw is it determined?