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need only C part ..with explanation
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Solved in 2 steps
- (1) Which has a single enolizable Hydrogen? (2) Which of the following produces an aldol and an α,β-unsaturated compound as the final product in simple aldol condensation reaction? (3) Which of these yields the same product with MNO when reacted with NH2NH2, KOH? (4) Which does not have an acidic Hydrogen?From the given structures which is(a) an acid halide? (b) a secondary amide (c) an aldehyde incapable of self-aldol consensation?1. Discuss the role of the Aldol condensation reaction in the synthesis below. What specific reaction was used in the synthesis? What is the importance of the aldol reaction in the entire synthetic approach? 2. Show the detailed reaction mechanism involved in their corresponding specific parts in this syntheses.
- In your investigations into the synthesis of condensation product B (aldol reaction), did temperature play any role in the outcome? Give a few words of explanation for why this might be. Aldehydes : Benzaldehyde, 2,2-Dimethyl-pentan-3-one Bases: KOH or LDA Solvents: Ethanol, Ether Reactions: Benzaldehyde + 2,2-Dimethyl-pentan-3-one + Ethanol + KOH or LDA Benzaldehyde 2,2-Dimethyl-pentan-3-one + Ether + KOH or LDAFor each pair, predict the stronger nucleophile in the SN2 reaction (using an alcohol asthe solvent). Explain your prediction.(a) (CH3CH2)3N or (CH3CH2)2NHAll are true or false a) The initially formed b-hydroxy carbonyl compound loses water in a Aldol condensation. b) Equilibrium favors the starting materials with both aldehydes and ketones for Aldol reactions. c)The Claisen reaction is a type of nucleophilic addition? d) The b-hydroxy carbonyl product of an Aldol reaction is oftentimes not the final isolated product. e)b-Ketoester and an enolate are the two starting materials for a Robinson annulation
- Your aldol condensation procedure calls for refluxing vanillin in acetone and NaOH for an hour. Whatmight happen if you didn’t heat the reaction, or heated it for too short a time? a) A mixture of aldol products and hydroxyketone intermediates would form.b) No reaction would occur, as the heat is needed to deprotonate the acetone.c) The reaction would still be successful.d) No reaction would occur, as the heat is needed to dissolve the NaOH.Illustrate the steps of a directed aldol reaction between a ketoneand an aldehyde, both of which have α hydrogens ?Which side product could be expected in this reaction if the product of the first addition, benzalacetone, reacts with acetone instead of the benzaldehyde? please show the structure of the side product and the mechanistic step(s) showing how it is formed. thanks in advance
- Vanillin has an acidic OH and an electrophilic aldehyde group that could conceivably react with sodiumhydroxide. However, in the aldol reaction, you added the NaOH directly to the solution of vanillin andacetone, rather than pre-treating acetone with base. Why could you do this successfully? a) NaOH is a weak base and a weak nucleophile.b) The reaction of NaOH with phenol OH groups and aromatic aldehydes is reversible, and thereaction is driven to the most stable product.c) The aldehyde in vanillin is unreactive towards nucleophiles.d) The NaOH is not soluble in the reactionunder each compound write "activating" or "deactivating" rings. "ortho-para" por ortho-para directing rings, or "meta" for meta-directing rings. Also write "No F.C." under any compound that will not undergo friedel-craft acylation or alkylationAttached compounds undergoes E2 elimination with strongbase? For compounds that undergo elimination, draw the product. Forcompounds that do not undergo elimination, explain why they are unreactive.