or a program execution, Step 1 is completed in the below diagram by filling the required CPU registers (PC, AC and IR). Fill the same registers for remaining steps. The contents of memory are shown hexadecimal and the list of opcodes is as under:

Systems Architecture
7th Edition
ISBN:9781305080195
Author:Stephen D. Burd
Publisher:Stephen D. Burd
Chapter6: System Integration And Performance
Section: Chapter Questions
Problem 12VE
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For a program execution, Step 1 is completed in the below diagram by filling the required CPU registers (PC, AC and IR). Fill the same registers for remaining steps. The contents of memory are shown hexadecimal and the list of opcodes is as under:

0001 =Load AC from Memory
0010 = Store AC to Memory
0101 = A dd to AC from Memory
er:
CPU Registers
5 70 PC
Memory
Memory
CPU Registers
570 18 3 5
571 5 8 3 6
572 2 8 3 6
570 1 8 3 5
AC571 5 8 3 6
1835 IR 572 2 8 36
PC
AC
IR
835 0 0 0 6
836 0 0 0 2
835 0 0 0 6
836 0 0 0 2
Step 1
Step 2
CPU Registers
PC
AC
CPU Registers
Memory
Memory
570 1 8 3 5
571 5 8 3 6
572 2 8 3 6
PC
570 1 8 3 5
AC571 5 8 3 6
IR 572 2 8 36
IR
835 0 0 0 6
836 0 0 0 2
0 006
835
836 0 0 0 2
Step 3
Step 4
Memory
CPU Registers
Memory
CPU Registers
PC
PC
570 1 8 3 5
571 5 8 3 6
572 2 8 3 6
570 1 8 3 5
AC571 5 8 3 6
IR 572 2 8 3 6
AC
IR
835 0 0 0 6
836 0 0 0 2
835 0 0 0 6
836 0 0 0 2
Step 5
Step 6
Transcribed Image Text:0001 =Load AC from Memory 0010 = Store AC to Memory 0101 = A dd to AC from Memory er: CPU Registers 5 70 PC Memory Memory CPU Registers 570 18 3 5 571 5 8 3 6 572 2 8 3 6 570 1 8 3 5 AC571 5 8 3 6 1835 IR 572 2 8 36 PC AC IR 835 0 0 0 6 836 0 0 0 2 835 0 0 0 6 836 0 0 0 2 Step 1 Step 2 CPU Registers PC AC CPU Registers Memory Memory 570 1 8 3 5 571 5 8 3 6 572 2 8 3 6 PC 570 1 8 3 5 AC571 5 8 3 6 IR 572 2 8 36 IR 835 0 0 0 6 836 0 0 0 2 0 006 835 836 0 0 0 2 Step 3 Step 4 Memory CPU Registers Memory CPU Registers PC PC 570 1 8 3 5 571 5 8 3 6 572 2 8 3 6 570 1 8 3 5 AC571 5 8 3 6 IR 572 2 8 3 6 AC IR 835 0 0 0 6 836 0 0 0 2 835 0 0 0 6 836 0 0 0 2 Step 5 Step 6
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