You see the rate you choose from part B, estimate the value of the car to be at 150,000 miles. explain how you got your answer $14,000$12,000$10,000$8,000Car'sValue$6,000$4,000$2,000$020000400006000080000100000120000Mileage b. What is the overall rate of change of this graph from 0 to 120,000whmiles? Write your answer as a unit rate and in a completesentence.3000-1400012000-0-1100012000=-11/12The overall rate of change of this graph from 0 to 120,000 miles is-0.916 dollars per mileage.

Answered: ou see the rate you choose from part B,…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

See similar textbooks

Related questions

Concept explainers

Question

You see the rate you choose from part B, estimate the value of the car to be at 150,000 miles. explain how you got your answer

$14,000
$12,000
$10,000
$8,000
Car's
Value
$6,000
$4,000
$2,000
$0
20000
40000
60000
80000
100000
120000
Mileage

b. What is the overall rate of change of this graph from 0 to 120,000
whmiles? Write your answer as a unit rate and in a complete
sentence.
3000-14000
12000-0
-11000
12000
=-11/12
The overall rate of change of this graph from 0 to 120,000 miles is
-0.916 dollars per mileage.

Expert Solution

Step 1

The average rate of change of this graph from 0 to 120,000 is:

$\begin{array}{rcl} A & = & \frac{3, 000 - 14, 000}{120, 000 - 0} \\ = & \frac{- 11, 000}{120, 000} \\ = & - \frac{11}{120} \\ = & - 0.0916 \end{array}$

Therefore, the average rate of change of this graph from 0 to 120,000 miles is -0.0916 dollars per mileage.

Consider the secant line passing through the points $(0, 14000)$ and $(120000, 3000)$ .

Note that the slope of the secant line is equal to the average rate of change of the graph.

Therefore, the slope of the secant line is -0.0916.

Hence, the equation of the secant line is:

$\begin{array}{rcl} y - 14, 000 & = & (- 0.0916) (x - 0) \\ y & = & - 0.0916 x + 14, 000 \end{array}$

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Single Variable$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, advanced-math and related others by exploring similar questions and additional content below.

Recommended textbooks for you

Advanced Engineering Mathematics

Advanced Math

ISBN:

9780470458365

Author:

Erwin Kreyszig

Publisher:

Wiley, John & Sons, Incorporated