Pard - 30 hp V; - 240 V "ted - 1800 r/min R-0.19 Q R -0.02 N Iend - 110 A N, - 2700 turns per pole Ngg - 14 turns per pole R, - 75 2 R - 100 to 400 N %3D
Pard - 30 hp V; - 240 V "ted - 1800 r/min R-0.19 Q R -0.02 N Iend - 110 A N, - 2700 turns per pole Ngg - 14 turns per pole R, - 75 2 R - 100 to 400 N %3D
Chapter19: Special-purpose Outlets-water Pump, Water Heater
Section19.2: Water Heater Branch Circuit
Problem 1R
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Transcribed Image Text:Ied - 110 A
N - 2700 turns per pole
NSE - 14 turns per pole
Prd - 30 hp
V, = 240 V
ned - 1800 r/min
R -0.19 Q
R = 0.02 N
R, - 75 Q
R = 100 to 400 2
Magnetization curve
300
280
260
Speed - 1800 r/in
240
220
> 200
180
160
140
120
100
80
60
40
20
0 0.1 02 0.3 0.4 0.5 0.6 0.7 0.8 0.9
1 1.1 12 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2
Shunt field curent, A
The motor is connected in shunt. If Radj can be adjusted from 100 to 400 W, what are the maximum and minimum no-load speeds possible with this motor?
NOTE: Magnetization curve is given for 1800 rpm.
(a) Maximum speed in rpm
(b) Minimum speed in rpm
Internal generated voltage E, V
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