Part AHow many grams of CaCl, are formed when 15.00 mL of 0.00237 M Ca(OH), reacts with excess Ch gas?2 Ca(OH)2(aq) + 2 Cl2(g) → Ca(OCI)2(aq) + CaCl½(s) + 2 H20()0.00789 gO 0.00197 gO 0.00394 gO 0.0507 gSubmitRequest AnswerProvide FeedbackNext >

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Part A How many grams of CaC, are formed when 15.00 mL of 0.00237 M Ca(OH), reacts with excess Cl, gas? 2 Ca(OH)2(aq) + 2 Cl½(9) → Ca(OCI);(aq) + CaCH(s) + 2 H2O(1) O 0.00789 g O 0.00197 g O 0.00394 g O 0.0507 g Submit Reguest Answer Provide Feedback

Part A How many grams of CaC, are formed when 15.00 mL of 0.00237 M Ca(OH), reacts with excess Cl, gas? 2 Ca(OH)2(aq) + 2 Cl½(9) → Ca(OCI);(aq) + CaCH(s) + 2 H2O(1) O 0.00789 g O 0.00197 g O 0.00394 g O 0.0507 g Submit Reguest Answer Provide Feedback

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter3: Chemical Reactions

Section: Chapter Questions

Problem 95QRT

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

Part A
How many grams of CaCl, are formed when 15.00 mL of 0.00237 M Ca(OH), reacts with excess Ch gas?
2 Ca(OH)2(aq) + 2 Cl2(g) → Ca(OCI)2(aq) + CaCl½(s) + 2 H20()
0.00789 g
O 0.00197 g
O 0.00394 g
O 0.0507 g
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