Part A. 1. Write equations to describe what happened when: a. Carbon dioxide was dissolved in water. co2(g) + H2O() <-> H2CO3(aq) <--> HC03-(aq) + H3O+(aq) b. When the indicator bromothymol blue was added to cold water. Hin(aq) + H20() <-> H3O+(aq) + In-(aq) C. From equations la and lb above, when NaOH was added to flasks A and B, why did the indicator initially turn blue? Explain your answer in terms of the equilibrium of equation 1b. Then you left the two flasks to stand for several minutes after the addition of NaOH, why did the contents of flask A again change colour back from blue to yellow? Explain your answer in terms of the equilibrium in lb above. The time delay for the second colour change back to yellow implies that the overall speed of the two-step conversion of carbon dioxide shown as equation (8) on page D7 is slow. Which is the slow step? Explain the basis of your answer.

Fundamentals Of Analytical Chemistry
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ISBN:9781285640686
Author:Skoog
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Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.40QAP
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Part A.
1. Write equations to describe what happened when:
a. Carbon dioxide was dissolved in water.
C2(g) + H20() <-> H2CO3(aq) <--> HCO3-(aq) + H30+(aq)
b. When the indicator bromothymol blue was added to cold water.
Hin(aq) + H20() <-> H3O+(aq) + In-(aq)
C. From equations la and lb above, when NaOH was added to flasks A and B, why did the
indicator initially turn blue? Explain your answer in terms of the equilibrium of equation 1b.
Then you left the two flasks to stand for several minutes after the addition of NaOH, why did
the contents of flask A again change colour back from blue to yellow? Explain your answer in
terms of the equilibrium in 1b above.
The time delay for the second colour change back to yellow implies that the overall speed of
the two-step conversion of carbon dioxide shown as equation (8) on page D7 is slow. Which
is the slow step? Explain the basis of your answer.
Transcribed Image Text:Part A. 1. Write equations to describe what happened when: a. Carbon dioxide was dissolved in water. C2(g) + H20() <-> H2CO3(aq) <--> HCO3-(aq) + H30+(aq) b. When the indicator bromothymol blue was added to cold water. Hin(aq) + H20() <-> H3O+(aq) + In-(aq) C. From equations la and lb above, when NaOH was added to flasks A and B, why did the indicator initially turn blue? Explain your answer in terms of the equilibrium of equation 1b. Then you left the two flasks to stand for several minutes after the addition of NaOH, why did the contents of flask A again change colour back from blue to yellow? Explain your answer in terms of the equilibrium in 1b above. The time delay for the second colour change back to yellow implies that the overall speed of the two-step conversion of carbon dioxide shown as equation (8) on page D7 is slow. Which is the slow step? Explain the basis of your answer.
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