Recall that the work WWW done by a constant force F⃗ F→F_vec at an angle θθtheta to the displacement Δr⃗ Δr→ isW=F⃗ ⋅Δr⃗ =FΔrcosθW=F→⋅Δr→=FΔrcos⁡θ.The vector magnitudes FFF and ΔrΔr are always positive, so the sign of WWW is determined entirely by the angle θθtheta between the force and the displacement.What is the work WTWT done by the tension force?Express your answers in joules to two significant figures. I Review I ConstantsLearning Goal:To practice Tactics Box 9.1 Calculating the Work Done by aConstant Force.Part BRecall that the work W done by a constant force F at an angle 0to the displacement Ar isWhat is the work Wn done on the box by the normal force?Express your answers in joules to two significant figures.W = F. Ar = FAr cos 0.• View Available Hint(s)The vector magnitudes F and Ar are always positive, so thesign of W is determined entirely by the angle 0 between the forceand the displacement.Wn = 0 JSubmitPrevious AnswersCorrectBecause there is no component of the normal force in the direction of motion, the normal force does no work on the box.Part CWhat is the work WT done by the tension force?Express your answers in joules to two significant figures.• View Available Hint(s)Figure1 of 1ΑΣΦ?WT =- 0.92J47SubmitPrevious AnswersX Incorrect; Try Again; 4 attempts remainingProvide FeedbackNext > II Review l ConstantsLearning Goal:To practice Tactics Box 9.1 Calculating the Work Done by aConstant Force.TACTICS BOX 9.1 Calculating the work done by a constant forceSign ofWForce and displacementWork WEnergy transferRecall that the work W done by a constant force F at an angle 0to the displacement Ar isW = F· AF = FAr cos 0.AF0°F(Ar)+The vector magnitudes F and Ar are always positive, so thesign of W is determined entirely by the angle 0 between the forceand the displacement.Energy is transferred into the system. The particle speeds up. Kincreases.AF< 90° | F(Ar) cos 0+90°No energy is transferred. Speed and K are constant.AF> 90° F(Ar) cos 0Energy is transferred out of the system. The particle slows down. Kdecreases.Figure1 of 1AF180°-F(Ar)A box with weight of magnitude FGin (Figure 1) at left. The normal force acting on the box has a magnitude n =down the inclined plane.2.00 N is lowered by a rope down a smooth plane that is inclined at an angle o = 30.0 ° above the horizontal, as shown1.73 N, the tension force is 1.00 N, and the displacement A7 of the box is 1.80 mPart A平

Name: Recall that the work WWW done by a constant force F⃗ F→F_vec at an ang
Uploaded: 2024-03-20T06:57:16.000Z
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Description: Recall that the work WWW done by a constant force F⃗ F→F_vec at an angle θθtheta to the displacement Δr⃗ Δr→ isW=F⃗ ⋅Δr⃗ =FΔrcosθW=F→⋅Δr→=FΔrcos⁡θ.The vector magnitudes FFF and ΔrΔr are always positive, so the sign of WWW is determined entirely by th