   Chapter 5, Problem 2P

Chapter
Section
Textbook Problem

In 1990 Walter Arfeuille of Belgium lifted a 281.5-kg object through a distance of 17.1 cm using only his teeth. (a) How much work did Arfeuille do on the object? (b) What magnitude force did he exert on the object during the lift, assuming the force was constant?

(a)

To determine
The work done on the object.

Explanation

Given Info:

The weight of the object is 281.5kg .

The height to which the object is lifted is 17.1cm .

Formula to calculate the work done on the object is,

W=ΔKE+ΔPE

• ΔKE is the change in kinetic energy
• ΔPE is the change in potential energy

Since, the assumption is, the lifter lifts the object in a constant speed; change in kinetic energy of the object is zero.

So the work done on the object is,

W=ΔPE=mgh

• m is the mass of the object
• g is acceleration due to gravity
• h is the height with which the object is lifted

Substitute 281.5kg for m, 9.8m/s2 for g and 17

(b)

To determine
The magnitude of force the lifter applied on the object when he lifts the object.

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