PART D: OMIT INITIALGiven 2 strings, str1 and str2, print out their concatenation, except omit the first character of each. Assumethe string will be at least length 1.Methods to use: substring(), length()Testing cases: Hello,There => ellohere java,code => avaode shotl,java => hotlava ab,xy => by ab,x => b x,ac => c a,x => (empty string)kit,kat => itat mart,dart => artart

PART D: OMIT INITIALGiven 2 strings, str1 and str2, print out their concatenation, except omit the first character of each. Assumethe string will be at least length 1.Methods to use: substring(), length()Testing cases: Hello,There => ellohere java,code => avaode shotl,java => hotlava ab,xy => by ab,x => b x,ac => c a,x => (empty string)kit,kat => itat mart,dart => artart

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter7: Characters, Strings, And The Stringbuilder

Section: Chapter Questions

Problem 16RQ

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PART G: COUNT HIGiven a string str, output the number of times the string “hi” appears anywhere in the string. Methods to use: substring(), length(), equals()Testing cases:abc hi ho => 1 ABChi hi => 2 hihi => 2 hiHIhi => 2 h => 0 hi => 1 Hi is no HI on ahI => 0 hiho not HOHIhi => 2
The following code fragment attempts to print out a string in uppercase letters: public void printUpper(String s){s.toUpperCase();System.out.println(s);} This code, however, does not work. Find out why, and explain. How should it be written properly?
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def is_palindrome_string(string: str) -> bool:"""Given a string <string>, return whether this string is a palindrome string.for ANY CONTINUOUS SEGMENT OF ALPHABETICAL CHARACTERS. That means that "abc;def", has two words: "abc"and "def". The separating character does not have to be whitespace, andthere could be more than one separating character between two words.A simple example: given the string "test string test", there are threewords, "test", "string", and "test". The first letters of each word cometogether to form the string "tst". And since "tst" is a palindrome, thisfunction should return True for the input "test string test".Precondition: <string> will contain at least one word.""" " please code this in python and also add this code def is_palindrome(string: str) -> bool:string = string.replace(" ", "")return string.lower() == string[::-1].lower() and use is_palindrome in the main function "
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