2. Write the method named countChar() * * You are given a String str, and a char ch. * Return the number of times that ch appears * inside str, but ignore case. * * Oh, and you can't use the classification methods * in the Character class. Use plain if statements, * remembering that you can check if ch is lowercase * by checking if it is between lowercase 'a' and * lowercase 'z', inclusive. Likewise, check if * between 'A' and 'Z' for capital. To convert lowercase to * uppercase, subtract the difference between lowercase 'a' * and uppercase 'A' ('a'-'A') from the lowercase character. * Add this difference to convert from uppercase to lowercase. * * Examples: * countChar("Abcdefg", 'a') returns 1 * countChar("xxXx", 'x') returns 4 * countChar("", 'q') returns 0 * * @param str the String to search through * @param ch the char to count (not case sensitive) * @return the count of ch in str */ public int countChar(String str, char ch) { // Complete the countChar method here } }

Please help me! I have a lot of mini problems. I'm not sure how to start After #6, I have other problems. Those are : 7.) Write a method that reads a one-line sentence as input and then displays the following response: If the sentence ends with a question mark (?) and the input contains an even number of characters, display the word Yes. If the sentence ends with a question mark and the input contains an odd number of characters, display the word No. If the sentence ends with an exclamation point (!), display the word Wow. In all other cases, display the words You always say followed by the input string enclosed in quotes. Your output should all be on one line. Be sure to note that in the last case, your output must include quotation marks around the echoed input string. In all other cases, there are no quotes in the output. Your program does not have to check the input to see that the user has entered a legitimate sentence. Notes: This code requires a three-way selection statement and…

Use java language  Write the method named oddSum();* * Given a String str return the arithmetic sum * of the odd-numbered digits '1'-'9' that appear in the string, * ignoring all other characters. Return 0 if there * are no digit characters in the string.** You cannot use any of the classification methods in* the Character class. You must use the relational operators* and simple logic to decide if a character is a digit.* (A character is a digit if it is between '0' and '9',* inclusive. Notice these are char literals, not int literals.)* To convert a digit character to a integer number, simply* subtract the character '0'. For example, '7' - '0' --> 7.* (Notice that subtracting two char results in an int.)** Examples:* oddSum("aa1bc2d3") returns 4 (2 is even)* oddSum("aa11b33") returns 8* oddSum("") returns 0* * @param str the String search for digits* @return the sum of the digits odd digits

Please help me fix this program. It is constantly saying I have duplicates of class main and many more Main. Java is below as well as my gui which is the photos (the gui is my problem) import java.util.*; public class Main { //Inputs a one character string and returns True if the character is a letter (i.e. a to z or A to Z). Returns false if it is not. A function to check that the password or encryption key is valid. public static boolean isALetter(char letter){ if( (letter >= 'a' && letter = 'A' && letter =-32767 && encryptKey