Paula is considering the purchase of a new car. She has narrowed her search to two cars that are equally appealing to her. Car A costs $29,000, and Car B costs $29,500. The manufacturer of Car A is offering 0% financing for 48 months with zero down, while the manufacturer of Car B is offering a rebate of $2000 at the time of purchase plus financing at the rate of 3%/year compounded monthly over 48 months with zero down. If Paula has decided to buy the car with the lower net cost to her, which car should she purchase? (Round numerical values to the nearest cent.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Paula is considering the purchase of a new car. She has narrowed her search to two cars that are equally appealing to her. Car A costs $29,000, and Car B costs $29,500. The manufacturer of Car A is offering 0% financing for 48 months with zero down, while the manufacturer of Car B is offering a rebate of $2000 at the time of purchase plus financing at the rate of 3%/year compounded monthly over 48 months with zero down. If Paula has decided to buy the car with the lower net cost to her, which car should she purchase? (Round numerical values to the nearest cent.

Expert Solution
calculating net cost for Car B

For Car B:

Total Price = $29,500

Rebate =$2000

Net Price =$29,500-$2000 =$27,500

Rate (R) =3% Compounded Monthly

Time(n) = 48 months = 4 Years

It is given that it is compounded monthly, 

Hence,

A=Principal1+R12×10012(4)   =(27500)1+3120048   =$31001.5206

Hence, after financing car B costs a total of $31001.5206

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