PCIS(s) can be prepared by the reaction PCla(l) + Cl2(g) PCls(s). Calculate the enthalpy change (in kJ) that accompanies the production of 100.0 g of PCis(s) by the above reaction, given the following data. Pals) + 6 Cl2(g) - 4 PCI3(1) AH = -1280 kJ per mole of P4(s) %3D Pa(s) + 10 Cl2(g) - 4 PCI5(s) AH = -1774 kJ per mole of P4(s) O-124 -258 +124 O+59.3 -59.3

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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.132QP
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PCIS(s) can be prepared by the reaction PCl3(0) + Cl2(g) PCls(s). Calculate the
enthalpy change (in kJ) that accompanies the production of 100.0 g of PCIs(s) by the
above reaction, given the following data.
Pals) + 6 Cl2(g)
-4 PCI3(1)
AH° = -1280 kJ per mole of P4(s)
Pa(s) + 10 Cl2(g)
-4 PCI5(s)
AH =
-1774 kJ per mole of P4(s)
-124
O-258
O+124
O+59.3
O-59.3
Transcribed Image Text:PCIS(s) can be prepared by the reaction PCl3(0) + Cl2(g) PCls(s). Calculate the enthalpy change (in kJ) that accompanies the production of 100.0 g of PCIs(s) by the above reaction, given the following data. Pals) + 6 Cl2(g) -4 PCI3(1) AH° = -1280 kJ per mole of P4(s) Pa(s) + 10 Cl2(g) -4 PCI5(s) AH = -1774 kJ per mole of P4(s) -124 O-258 O+124 O+59.3 O-59.3
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