P(exactly two children are cured) (Round to three decimal places as needed.) g. Without using the binomial probability formula, obtain the probability distribution of the random variable X, the number of children out of three who are cured. X 0 1 2 3 P(X=x) (Round to three decimal places as needed.) Help me solve this View an example Get more help.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.1: Measures Of Center
Problem 14PPS
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inworm infestation, commonly found in children, can be treated with a drug that is effective in 92% of cases. Suppose that three children with pinworm infestation are given the drug. Complete parts (a) through (g) be
C
d. List the outcomes in which exactly two of the three children are cured. (Let s be a success and f be a failure.)
SSF,SFS,FSS (Use a comma to separate answers as needed.)
e. Find the probability of each outcome in part (d). Why are those probabilities all the same?
Each outcome in part (d) has the probability 0.068.
(Round to three decimal places as needed.)
Why are those probabilities all the same?
OA. The probability is the same because each outcome is the same.
B. The probability is the same for each outcome because each probability is obtained by multiplying two success probabilities of 0.92 and one failure probability of 0.08.
OC. The probability is the same for each outcome because each probability is obtained by multiplying one success probability of 0.08 and one failure probability of 0.92.
OD. The probability is the same for each outcome because each probability is obtained by multiplying one success probability of 0.08 and two failure probabilities of 0.92.
f. Use parts (d) and (e) to determine the probability that exactly two of the three children will be cured.
P(exactly two children are cured)= 0.203
(Round to three decimal places as needed.)
g. Without using the binomial probability formula, obtain the probability distribution of the random variable X, the number of children out of three who are cured.
0
x
1
2
3
P(X=x)
(Round to three decimal places as needed.)
Help me solve this View an example
Get more help .
A
MacBook A
st
20
000
COD
F2
F3
F4
F6
esc
!
1
A
F1
@
2
W
S
#
3
E
D
$
4
R
F
%
5
F5
T
G
6
Y
11
Transcribed Image Text:inworm infestation, commonly found in children, can be treated with a drug that is effective in 92% of cases. Suppose that three children with pinworm infestation are given the drug. Complete parts (a) through (g) be C d. List the outcomes in which exactly two of the three children are cured. (Let s be a success and f be a failure.) SSF,SFS,FSS (Use a comma to separate answers as needed.) e. Find the probability of each outcome in part (d). Why are those probabilities all the same? Each outcome in part (d) has the probability 0.068. (Round to three decimal places as needed.) Why are those probabilities all the same? OA. The probability is the same because each outcome is the same. B. The probability is the same for each outcome because each probability is obtained by multiplying two success probabilities of 0.92 and one failure probability of 0.08. OC. The probability is the same for each outcome because each probability is obtained by multiplying one success probability of 0.08 and one failure probability of 0.92. OD. The probability is the same for each outcome because each probability is obtained by multiplying one success probability of 0.08 and two failure probabilities of 0.92. f. Use parts (d) and (e) to determine the probability that exactly two of the three children will be cured. P(exactly two children are cured)= 0.203 (Round to three decimal places as needed.) g. Without using the binomial probability formula, obtain the probability distribution of the random variable X, the number of children out of three who are cured. 0 x 1 2 3 P(X=x) (Round to three decimal places as needed.) Help me solve this View an example Get more help . A MacBook A st 20 000 COD F2 F3 F4 F6 esc ! 1 A F1 @ 2 W S # 3 E D $ 4 R F % 5 F5 T G 6 Y 11
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