Phthalonitrile (C₈H₄N₂) is produced by the ammoxidation of o-xylene (C₈H₁₀) according to the following reaction: C₈H₁₀(l) + O₂(g) + NH₃(g) → C₈H₄N₂(s) + H₂O(l) How many grams of water would be produced by the complete ammoxidation of 17.8 moles of o-xylene?
Phthalonitrile (C₈H₄N₂) is produced by the ammoxidation of o-xylene (C₈H₁₀) according to the following reaction: C₈H₁₀(l) + O₂(g) + NH₃(g) → C₈H₄N₂(s) + H₂O(l) How many grams of water would be produced by the complete ammoxidation of 17.8 moles of o-xylene?
General, Organic, and Biological Chemistry
7th Edition
ISBN:9781285853918
Author:H. Stephen Stoker
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Chapter6: Chemical Calculations: Formula Masses, Moles, And Chemical Equations
Section: Chapter Questions
Problem 6.68EP: How many carbon monoxide molecules (CO) are needed to react with 8 hydrogen molecules (H2) to...
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Phthalonitrile (C₈H₄N₂) is produced by the ammoxidation of o-xylene (C₈H₁₀) according to the following reaction: C₈H₁₀(l) + O₂(g) + NH₃(g) → C₈H₄N₂(s) + H₂O(l) How many grams of water would be produced by the complete ammoxidation of 17.8 moles of o-xylene?
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