When benzene (C6H6) reacts with bromine (Br)2, bromobenzene(C6H5Br) is obtained:C6H6 + Br2-------->C6H5Br + HBr(a) When 30.0 g of benzene reacts with 65.0 g of bromine, whatis the theoretical yield of bromobenzene? (b) If the actual yieldof bromobenzene is 42.3 g, what is the percentage yield?

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