QUESTION 32 In a version of Millikan's experiment, an oil droplet is released and when it has travelled a distance d1, the electric field is switched on with a magnitude such that at distance dɔ the droplet velocity has been reduced to zero. Calculate the charge on the droplet. Give you answer in equivalent charge of how many electrons. Distance d1: 0.07 m Distance between plates: 0 1 m Distance d2 - d1: 0.012m mass of droplet 3.65x10 16 Kg Voltage difference: 332.1037138 10 'n 本 Click Save amd Submit to save and submit. Click Save All Answers to save all answers. 6°C Clou O1

QUESTION 32 In a version of Millikan's experiment, an oil droplet is released and when it has travelled a distance d1, the electric field is switched on with a magnitude such that at distance dɔ the droplet velocity has been reduced to zero. Calculate the charge on the droplet. Give you answer in equivalent charge of how many electrons. Distance d1: 0.07 m Distance between plates: 0 1 m Distance d2 - d1: 0.012m mass of droplet 3.65x10 16 Kg Voltage difference: 332.1037138 10 'n 本 Click Save amd Submit to save and submit. Click Save All Answers to save all answers. 6°C Clou O1

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter30: Atomic Physics

Section: Chapter Questions

Problem 56PE: Integrated Concepts In a Millikan oil-drop experiment using a setup like that in Figure 30.9, a...

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Integrated Concepts In a Millikan oil-drop experiment using a setup like that in Figure 30.9, a 500-V potential difference is applied to plates separated by 2.50 cm. (a) What is the mass of an oil drop having two extra electrons that is suspended motionless by the field between the plates? (b) What is the diameter of the drop, assuming it is a sphere with the density of olive oil?
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A Thomson-type experiment with relativistic electrons. One of the earliest experiments to show that p = mv (rather than p = mv) was that of Neumann. [G. Neumann, Ann. Physik 45:529 (1914)]. The apparatus shown in Figure P4.5 is identical to Thomsons except that the source of high-speed electrons is a radioactive radium source and the magnetic field B is arranged to act on the electron over its entire trajectory from source to detector. The combined electric and magnetic fields act as a velocity selector, only passing electrons with speed v, where v = V/Bd (Equation 4.6), while in the region where there is only a magnetic field the electron moves in a circle of radius r, with r given by p = Bre. This latter region (E = 0, B = constant) acts as a momentum selector because electrons with larger momenta have paths with larger radii. (a) Show that the radius of the circle described by the electron is given by r = (l2 + y2)/2y. (b) Typical values for the Neumann experiment were d = 2.51 104 m, B = 0.0177 T, and l = 0.0247 m. For V = 1060 V, y, the most critical value, was measured to be 0.0024 0.0005 m. Show that these values disagree with the y value calculated from p = mv but agree with the y value calculated from p = mv within experimental error. (Hint: Find v from Equation 4.6, use mv = Bre or mv = Bre to find r, and use r to find y.) Figure P4.5 The Neumann apparatus.