Please answer fast Gene B codes for purple-colored flowers while the recessive form of the gene (b) results in pink-colored flowers. Another gene, A, when dominant, activates the transcription of gene B, resulting in purple or pink-colored flowers, while the recessive version of aa, results in white-colored flowers. A homozygous purple-colored flowering plant was crossed with a fully homozygous recessive white-colored flowering plant. The F1 flowering plants were self-crossed to generate the F2 generation. Determine the phenotypes and genotypes for each generation. Explain.

Please answer fast Gene B codes for purple-colored flowers while the recessive form of the gene (b) results in pink-colored flowers. Another gene, A, when dominant, activates the transcription of gene B, resulting in purple or pink-colored flowers, while the recessive version of aa, results in white-colored flowers. A homozygous purple-colored flowering plant was crossed with a fully homozygous recessive white-colored flowering plant. The F1 flowering plants were self-crossed to generate the F2 generation. Determine the phenotypes and genotypes for each generation. Explain.

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Description: Please answer fastGene B codes for purple-colored flowers while the recessive form of the gene (b) results in pink-colored flowers. Another gene, A, when dominant, activates the transcription of gene B, resulting in purple or pink-colored flowers, wh

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter10: From Proteins To Phenotypes

Section: Chapter Questions

Problem 3CS: A couple was referred for genetic counseling because they wanted to know the chances of having a...

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PLEASE ANSWER THE FOLLOWING LETTERS: a,b,c, and d Examine the pedigree of the McGraw family shown below. Certain individuals in this family are affected by a brain condition that makes them more susceptible to vertigo. As a genetic counselor, you interview the family and draw DNA samples. You discover that the condition is caused by a mutation that changes the sequence 5’GCATTC3’ to 5’GAATTC3’ introducing an EcoRI cut site. You decide to amplify a 1200bp fragment from the DNA that spans this mutation and then digest it with EcoRI. You run the results on a gel next to a marker that shows bands at 2000bp, 1200bp, 900bp, 800bp, and 400bp. Some individuals from the pedigree are identified on the gel.
Drosophila, yellow body color is due to an X-linked gene that is recessive to the gene for gray body color.a. A homozygous gray female is crossed with a yellow male. The F1 are intercrossed to produce the F2. Give the genotypes and phenotypes, along with the expected proportions, of the F1 and F2 progeny.b. A yellow female is crossed with a gray male. The F1 are intercrossed to produce the F2. Give the genotypes and phenotypes, along with the expected proportions, of the F1 and F2 progeny.c. A yellow female is crossed with a gray male. The F1 females are backcrossed with gray males. Give the genotypes and phenotypes, along with the expected proportions, of the F2 progeny.d. If the F2 flies in part b mate randomly, what are the expected phenotypes and proportions of flies in the F3?
There are two genetic disorders that result from mutation in imprinted genes: Prader-Willi syndrome, Angelman syndrome. Angelman syndrome results from deletion of UBE3A, which is a gene imprinted such that only the maternal copy is expressed. In the pedigree above, individual I-1 is heterozygous for a deletion of UBE3A and does not have Angelman syndrome. Individual I-2 is homozygous wild type for UBE3A. Which individuals in the pedigree are at risk for exhibiting Angelman syndrome, if any? (Who could potentially have the syndrome, based on what alleles it is possible for them to inherit and express?) Question 8 options: Only I-1 could have been at risk. If he does not have the syndrome, no one in the pedigree could. Only III-1 is at risk I-1, II-2, and III-1 are all at risk Only II-2 is at risk No one in the pedigree is at risk Both II-2 and III-1 are at…
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
You are conducting independent research for your Honors Thesis in a Drosophila research lab. One of the graduate student researchers has provided you with two mutant strains of Drosophila. One has scarlet eyes, and the other has brown eyes. You cross homozygous scarlet-eyed male Drosophila with female flies homozygous for the brown-eye color allele, and all of the male and female F1 flies have wild-type eyes. Crosses involving F1 males x F1 females yield the results shown below. You know the traits involved are autosomal, and that reciprocal parental crosses produce similar results. A) Please define the alleles represented in this cross. B) List the genotypes of all classes of individuals in the P, F1, and F2Be sure to use the alleles you defined in Part A Parental (P) Generation Genotype of Homozygous scarlet-eyed males: Genotype of Homozygous brown-eyed females: F1 Generation: Genotype of Wild-type (red-eyed) males and females: F2 Generation: Genotype of wild-type males and…
You are conducting independent research for your Honors Thesis in a Drosophila research lab. One of the graduate student researchers has provided you with two mutant strains of Drosophila. One has scarlet eyes, and the other has brown eyes. You cross homozygous scarlet-eyed male Drosophila with female flies homozygous for the brown-eye color allele, and all of the male and female F1 flies have wild-type eyes. Crosses involving F1 males x F1 females yield the results shown below. You know the traits involved are autosomal, and that reciprocal parental crosses produce similar results. a) What is the phenotypic ration observed among the offspring in the F2 generation? b) How many pairs of genes are involved in determining these traits? Please explain in detail. c) Please EXPLAIN the genetic basis for the pattern of inheritance illustrated in this cross. Be sure to mention the alleles involved.
You are conducting independent research for your Honors Thesis in a Drosophila research lab. One of the graduate student researchers has provided you with two mutant strains of Drosophila. One has scarlet eyes, and the other has brown eyes. You cross homozygous scarlet-eyed male Drosophila with female flies homozygous for the brown-eye color allele, and all of the male and female F1 flies have wild-type eyes. Crosses involving F1 males x F1 females yield the results shown below. You know the traits involved are autosomal, and that reciprocal parental crosses produce similar results. a) What is the phenotypic ration observed among the offspring in the F2 generation? b) How many pairs of genes are involved in determining these traits? Please explain. c) Please EXPLAIN the genetic basis for the pattern of inheritance illustrated in this cross. Be sure to mention the alleles involved.
You are conducting independent research for your Honors Thesis in a Drosophila research lab. One of the graduate student researchers has provided you with two mutant strains of Drosophila. One has scarlet eyes, and the other has brown eyes. You cross homozygous scarlet-eyed male Drosophila with female flies homozygous for the brown-eye color allele, and all of the male and female F1 flies have wild-type eyes. Crosses involving F1 males x F1 females yield the results shown below. You know the traits involved are autosomal, and that reciprocal parental crosses produce similar results. A) Please define the alleles represented in this cross. B) List the genotypes of all classes of individuals in the P, F1, and F2Be sure to use the alleles you defined in Part A Parental (P) Generation Genotype of Homozygous scarlet-eyed males: Genotype of Homozygous brown-eyed females: F1 Generation: Genotype of Wild-type (red-eyed) males and females: F2 Generation: Genotype of wild-type males and…
You are conducting independent research for your Honors Thesis in a Drosophila research lab. One of the graduate student researchers has provided you with two mutant strains of Drosophila. One has scarlet eyes, and the other has brown eyes. You cross homozygous scarlet-eyed male Drosophila with female flies homozygous for the brown-eye color allele, and all of the male and female F1 flies have wild-type eyes. Crosses involving F1 males x F1 females yield the results shown in the image attached. You know the traits involved are autosomal, and that reciprocal parental crosses produce similar results. Another undergraduate researcher in your lab is studying mutations affecting the wings of Drosophila melanogaster. She has identified two mutant phenotypes of interest: bent wings (be), which are recessive to the wild-type straight wings (be+), and apterous (ap) mutants (which are wingless). The apallele is recessive to the wild-type allele (ap+), which allows wings to develop. If a…
Figure 5.1 presented abbreviated pedigrees looking at the inheritance of X-linked human conditions. El Figure 5.1a initiated with a male who was color blind and had hemophilia A. The grandsons and great-grandsons of this male were either color blind and had hemophilia A, or they had neither condition. a. Which if any individuals in the G Fig. 5.1a pedigree is a double heterozygote? b. Are any of the grandsons or great-grandsons shown in the pedigree the product of recombinant type gametes? c. Do the genes responsible for color blindness and hemophilia A segregate independently? d. If you examined many pedigrees, each starting with a man who was simultaneously color blind and had hemophilia A, do you think any grandsons or great-grandsons would ever have one condition but not the other? L Figure 5.1b initiated with a male who was color blind and had hemophilia B. The grandsons of this male were either only color blind, only had hemophilia B, had both conditions, or they had neither…