Please calculate the grams of each substance needed to make the following solutions: One-half (0.500) of a liter of 15.0 mM calcium sulfite solution For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph Arial 10pt E x X 深 +, !!!
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- Beaker 0.00200 M Fe(NO3)3, mL 0.00200 M NaSCN, mL total volume, mL 1 3.000 2.000 10.00 2 3.000 3.000 10.00 3 3.000 4.000 10.00 4 3.000 5.000 10.00 5 (blank) 3.000 0.000 10.00 In Solutions 1-4 you are adding successively larger volumes of 0.00200M SCN- to the Fe3+ solution and diluting to 10.00 ml. Calculate the final diluted molarity of SCN- in solution #1 Your answer should have 3 sig figs =Please answer this NEATLY, COMPLETELY, and CORRECTLY for an UPVOTE. From the stock solution (0.020 M), pipet 4.00 mL and dilute to 100.00 mL. From the diluted solution, pipet 0.00, 1.00, 1.50, 2.00, 2.50, 5.00 and 7.50 mL aliquots into 100 mL volumetric flasks. Dilute to mark. Determine the concentration of each standard solution and tabulate.Volume of an unknown used was 30 mL, Initial Buret volume was 0 and the Final Buret volume was 8.5 mL. What is the molarity of the unknown solution if the Net volume of NaOH being used was 8.5 mL and Millimoles (mmoles) NaOH reacted was 0.791? Then, what is the Mass (g) of Acetic Acid in unknown sample and thr average percent (%) Acetic Acid? (assume density = 1g/mL)
- Solve the required of the following and show the complete process to be able to gain the value of the correct answer. Given: Volume of Vinegar used (ml) = 25.00 mL Volume after dilution = 250.00 mL Volume of Aliquot used (ml) = 50.00 mL Volume NaOH used (ml) = 34.85 mL Concentration of NaOH = 0.09919475765 M Required: Calculate % (w/v) CH3COOH = ? P.S. Use weight in grams and volume of vinegar in mL, but correction based on aliquot should be made.Consider the titration illustrated in Figure 8.] Anhydrous sodium carbonate (Na₂CO₃) is a primary standard. When 0.364 grams of the substance is placed in a conical flask, then 20.00 cm³ of sulphuric acid (H₂SO₄) solution is required to reach the end point of the titration. What is the concentration in mol·dm⁻³ of the sulphuric acid solution? [Give the answer to 3 decimal places. Do not type in the unit. Use a decimal point.] *1-3: A stock solution of 70% v/v ethanol was diluted with distilled water to prepare 1L of 21% v/v ethanol. (Density of ethanol = 0.789 g/mL; MW of ethanol = 46 g/mol) Determine the initial volume of 70% v/v ethanol used in the preparation. How much water was added to the stock solution to make 1L of the final concentration? The molarity of 5.0 mL of 70% v/v ethanol was found to be __________.
- Part 1: Preparation of the Primary Citric Acid Standard Mass of empty 250-mL glass beaker: 100.7g Mass of 250-mL beaker and anhydrous citric acid First weighing : 103.4 g Second weighing: 106.5 g Third weighing: 106.1 3. Total volume of citric acid solution: 75.0 mL please help me with part Part 1: Preparation of the Primary Citric Acid Standard Mass of Citric Acid _________________________ Volume of Citric Acid Solution ____________ Moles of Citric Acid _________________ (Molar Mass = 192.0 g/mol) Molarity of Citric Acid Solution ____________A stock solution of 0.225 +/- 0.003 M NaNO2 was transferred to a 100 mL volumetric flask (class A) and diluted to the mark. If 7 mL of the stock solution was transferred using one 5-mL and two 1-mL volumetric pipettes, what is the new concentration of the solution and the uncertainty? Please show how to calculate the uncertainty, that is the one part I don't understand how to do1-3: A stock solution of 70% v/v ethanol was diluted with distilled water to prepare 1L of 21% v/v ethanol. (Density of ethanol = 0.789 g/mL; MW of ethanol = 46 g/mol) 1. Determine the initial volume of 70% v/v ethanol used in the preparation. 2. How much water was added to the stock solution to make 1L of the final concentration? 3. The molarity of 5.0 mL of 70% v/v ethanol was found to be __________. 4-6: A solution contains 45.0 g of methanol, CH3OH, dissolved in sufficient water to give a total mass of 210.6 g. 4. Compute for the number of moles of the solute present in the given solution. 5. What is the mass (in kg) of water used to dissolve the solute from the given problem? 6. Determine the molal concentration of the said solution.
- a 25.00 mL aliquot of vinegar was diluted to 250 mL in a volumetric flask. Titration of 50.00 mL aliquots of the diluted solution required an average of 34.88 mL of 0.09600 M NaOH. Express the acidity of the vinegar in terms of the percentage (w/v) of acetic acid (MM:60g/mol). Consider the correct significant figures of your answer and do not forget the unit.1.) Use the line of best ! Tables: Data Port 1. Synthesis of Asprin \table[[Mass of galicylic Acid used 2.024gt to calculate the concentration of the salicylic Acid in your asprin saple solution (in 50.0 ml volumettic flask) 2.) Use M1V1 = M2V2 to determine the concentration of salicylic acid in your 100.0 mL solution before dilutuon to 50.0mL for analysis. 3.) Determine the mass of salicylic acid present in the 4g sample of synthesized asprin tht was dissolved in the 100.0ml, volumetric flask 4.) Determine the percent of salicylic acid and percent asprin in the 4g sample of synthesized asprin7 5.) Calculate the theoretical yelld of asprin for your synthesis reaction. Assume that the salicylic acid used in the salicylic used in the synthesis reaction is the limiting reactant. 6. Determine the percent yild of the asprin for your synthesis. For the 1st cacization i got 1.340x10^-4 M C7H603 For the 2nd calculation i got M167x10^-5 Please check my calculations and explain the remainingmass of dish 1631.5 g mass of dish and mix 1822 g mass of dish and agg. after extraction 1791g mass of clean filter 25 g mass of filter after extraction 30 g mass of agg. in 150 ml solvent 1.2g if Ac% 5% find the volume of the solvent