PLEASE JUST EXPLAIN B NO NEED TO DO A  H3BO3 (aq) → HBO2 (aq) + H2O (l)              ΔH1 = - 0.02 kJ/mol  H2B4O7 (aq) + H2O (l) → 4HBO2 (aq)           ΔH2 = - 11.3 kJ/mol  H2B4O7 (aq) → 2B2O3 (s) + H2O (l)              ΔH3 = 17.5 kJ/mol    a)Find the ΔH for this overall reaction: 2H3BO3 (aq) → B2O3 (s) + 3H2O (l)

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PLEASE JUST EXPLAIN B NO NEED TO DO A 

H3BO3 (aq) → HBO2 (aq) + H2O (l)              ΔH1 = - 0.02 kJ/mol 

H2B4O(aq) + H2O (l) → 4HBO2 (aq)           ΔH2 = - 11.3 kJ/mol 

H2B4O7 (aq) → 2B2O3 (s) + H2O (l)              ΔH3 = 17.5 kJ/mol 

 

a)Find the ΔH for this overall reaction: 2H3BO3 (aq) → B2O3 (s) + 3H2O (l)

 

b)If 545 J of heat are absorbed or released from the reaction of 330. mL of H3BO3solution, what was the molarity of the solution?

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