Please no written by hand solutions A promising start-up wants to compete in the cell phone market. The start-up believes that the battery life of its cell phone is more than two hours longer than the leading product. A recent sample of 120 units of the leading product provides a mean battery life of 6 hours and 30 minutes with a standard deviation of 25 minutes. A similar analysis of 129 units of the start-up's product results in a mean battery life of 8 hours and 47 minutes and a standard deviation of 29 minutes. It is not reasonable to assume that the population variances of the two products are equal. All times are converted into minutes. Let new products and leading products represent population 1 and population 2, respectively. (You may find it useful to reference the appropriate table: table or table) a. Set up the hypotheses to test if the new product has a battery life more than two hours longer than the leading product. Но: Н1 - Н2 = 120; Нд: 1 - H2 # 120 • HO: M1 - 12 2 120: HA: M1 - H2 < 120 • HO: M1 - H2 5 120; HA: H1 - H2 > 120 b-1. Calculate the value of the test statistic. (Round final answer to 3 decimal places.) b-2. Find the p-value. • p-value < 0.01 O pivalue › 0.10 O 0.05 s p-value < 010 O 0.025 s p-value < 0.05 O 0.01 s pvalue < 0.025 b-3. At the 5% significance level, is the claim that the new product has n average, a battery life of more than two hours longer than the leading product is supported by the sample data? ______ H0. The claim that the new product has, on average, a battery life of more than two hours longer than the leading product is _____ by the sample data at the 5% significance level.
Please no written by hand solutions
A promising start-up wants to compete in the cell phone market. The start-up believes that the battery life of its cell phone is more than two hours longer than the leading product. A recent sample of 120 units of the leading product provides a mean battery life of 6 hours and 30 minutes with a standard deviation of 25 minutes. A similar analysis of 129 units of the start-up's product results in a mean battery life of 8 hours and 47 minutes and a standard deviation of 29 minutes. It is not reasonable to assume that the population variances of the two products are equal.
All times are converted into minutes. Let new products and leading products represent population 1 and population 2, respectively.
(You may find it useful to reference the appropriate table: table or table)
a. Set up the hypotheses to test if the new product has a battery life more than two hours longer than the leading product.
Но: Н1 - Н2 = 120; Нд: 1 - H2 # 120
• HO: M1 - 12 2 120: HA: M1 - H2 < 120
• HO: M1 - H2 5 120; HA: H1 - H2 > 120
b-1. Calculate the value of the test statistic. (Round final answer to 3 decimal places.)
b-2. Find the p-value.
• p-value < 0.01
O pivalue › 0.10
O 0.05 s p-value < 010
O 0.025 s p-value < 0.05
O 0.01 s pvalue < 0.025
b-3. At the 5% significance level, is the claim that the new product has n average, a battery life of more than two hours longer than the leading product is supported by the sample data?
______ H0. The claim that the new product has, on average, a battery life of more than two hours longer than the leading product is _____ by the sample data at the 5% significance level.
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