question 14 Please provide the IUPAC name (only) for the compound that best represents the spectroscopic data here:Molecular formula: C4H100Important IR data (cm1): 3280 (broad); 2910-2950 (many); 1053. All 'H NMR data shown as x.xx ppm (splitting), integration.1.23 ppm (t), 31.23 ppm (d), 3„HO-,4.03 ppm (m), 11.46 ppm (m), 2PPM

Answered: Image /qna-images/answer/45b4bd83-3d19-46da-9a1c-12f750b03bea.jpg

Please provide the IUPAC name (only) for the compound that best represents the spectroscopic data here: Molecular formula: C4H100 Important IR data (cm ): 3280 (broad); 2910-2950 (many); 1053 All 'H NMR data shown as x.Xx ppm (splitting), integration. 1.23 ppm (t), 3 1.23 ppm (d), 3 "-OH" 1.46 ppm (m), 2 4.03 ppm (m), 1 PPM 2.

Please provide the IUPAC name (only) for the compound that best represents the spectroscopic data here: Molecular formula: C4H100 Important IR data (cm ): 3280 (broad); 2910-2950 (many); 1053 All 'H NMR data shown as x.Xx ppm (splitting), integration. 1.23 ppm (t), 3 1.23 ppm (d), 3 "-OH" 1.46 ppm (m), 2 4.03 ppm (m), 1 PPM 2.

Macroscale and Microscale Organic Experiments

7th Edition

ISBN:9781305577190

Author:Kenneth L. Williamson, Katherine M. Masters

Publisher:Kenneth L. Williamson, Katherine M. Masters

Chapter13: Mass Spectrometry

Section: Chapter Questions

Problem 3Q

See similar textbooks

Similar questions

N-propylbenzene, C6H5CH2CH3, contains C (sp3) -H and C (sp2) -H bonds. Its IR spectrum shows strong or medium absorptions at 3085, 3064, 3028, 2960, 2931 and 2873 cm ^ -1, as well as bands below 1600cm -1. Which statement is wrong? A.) Stretching of the C (sp3) -H bonds results in absorptions at lower wave numbers than the stretching of the C (sp2) -H bonds. B.) The absorptions at 2960, 2931 and 2873 cm ^ -1 are assigned to stretching of the C (sp3) -H bonds. C.) The absorptions at 3085, 3064 and 3028 cm ^ -1they are assigned to stretching of the C (sp2) -H bonds. D.) Each absorption can be assigned to the stretch mode of a particular bond in the propylbenzene molecule.
Thymol (molecular formula C10H14O) is the major component of the oil ofthyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose apossible structure for thymol.
Compound 1, was found to consist of C,H,N, and Cl with an elemental analysis of 61.1% C, 2.9% H, and 10.2% N. IR Spectra displayed absorbances at 2215, 1605. Deduce the structure of this compound. (there is only one Cl)
compound with the molecular formula C7H9N exhibits IR bands at 3450 cm-1 (medium, doublet), and 855 cm-1 (strong) and shows the following major mass spectral signals (m/z): 106 (base); 107 (M+, about 70% of base), 91 (40% of base), and 77 (about 20% of base). Deduce a reasonable structure from this data.
Ethers are not easily differentiated by their infrared spectra, but they tend to form predictable fragments in the mass spectrum. The following compounds give similar butdistinctive mass spectra.O Obutyl propyl ether butyl isopropyl etherBoth compounds give prominent peaks at m>z 116, 73, 57, and 43. But one compoundgives a distinctive strong peak at 87, and the other compound gives a strong peak at 101.Determine which compound gives the peak at 87 and which one gives the peak at 101.Propose fragmentations to account for the ions at m>z 116, 101, 87, and 73.
c) FT-IR spectra of both nitro and nitrito-isomers were recorded immediately after preparation. Then small samples were exposed to heat (in oven) and their spectra were recorded again.
Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C. 2.Assign all peaks in 1H NMR spectrum of compounds B and C.
In the presence of a small amount of acid, a solution of acetaldehyde (CH3CHO) in methanol (CH3OH) was allowed to stand and a new compound L was formed. L has a molecular ion in its mass spectrum at 90 and IR absorptions at 2992 and 2941 cm−1. L shows three signals in its 13C NMR at 19, 52, and 101 ppm. The 1H NMR spectrum of L is given below. What is the structure of L?
2) Figures 2 to 4 show the IR, 1H NMR and 13C NMR spectra of a compound with formula C3H5N 2a) Identify bands A and B in the IR spectrum 2b) Using the information from the 1H NMR spectrum, fill in the table below Peak cluster (ppm) Multiplicity Number of H in neighbouring C Proposed identification 0 1.30 2.35 2c) Propose a structure for the compound C3H5N. Justify your answer by referring to key spectral features of the 3 spectra.
Reaction of pentanoyl chloride (CH3CH2CH2CH2COCl) with lithium dimethyl cuprate [LiCu(CH3)2] forms a compound J that has a molecular ion in its mass spectrum at 100, as well as fragments at m/z = 85, 57, and 43 (base). The IR spectrum of J has strong peaks at 2962 and 1718 cm-1. Propose a structure for J.
Treatment of benzaldehyde (C6H5CHO) with Zn(Hg) in aqueous HCl forms a compound Z that has a molecular ion at 92 in its mass spectrum. Z shows absorptions at 3150–2950, 1605, and 1496 cm-1 in its IR spectrum. Give a possible structure for Z.
2 The IR and 1H-NMR spectra of a compound with molecular formula C4H7ClO2 are shown below. Your objective as a group is to propose a structure for this compound, explaining how you reach your decision. Using all the information you have been given, in a post with others in your group share your initial ideas about the possible structure of the compound. Then use comments to interact with the other students in the group and propose a final answer to the problem. In the comment phase, you should comment on the postings of at least two other students.