Reaction of pentanoyl chloride (CH3CH2CH2CH2COCl) with lithium dimethyl cuprate [LiCu(CH3)2] forms a compound J that has a molecular ion in its mass spectrum at 100, as well as fragments at m/z = 85, 57, and 43 (base). The IR spectrum of J has strong peaks at 2962 and 1718 cm-1. Propose a structure for J.

Question
Asked Dec 27, 2019
1 views

Reaction of pentanoyl chloride (CH3CH2CH2CH2COCl) with lithium dimethyl cuprate [LiCu(CH3)2] forms a compound J that has a molecular ion in its mass spectrum at 100, as well as fragments at m/z = 85, 57, and 43 (base). The IR spectrum of J has strong peaks at 2962 and 1718 cm-1. Propose a structure for J.

check_circle

Expert Answer

Step 1

The reaction of pentanoyl chloride (CH3CH2CH2CH2COCl) with lithium dimethyl cuprate [LiCu(CH3)2] forms a compound J is given below :

Chemistry homework question answer, step 1, image 1
fullscreen
Step 2

The compound J formed is 2-hexanone, which forms a molecular ion with m/z value 100 as shown below :

Chemistry homework question answer, step 2, image 1
fullscreen
Step 3

Now, the various fragments of the molecular ion at m...

Chemistry homework question answer, step 3, image 1
fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Chemistry

Other

Related Chemistry Q&A

Find answers to questions asked by student like you
Show more Q&A
add