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Please show the major products with stereochemistry where needed.
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- Cocaine(C17H21O4N) is a natural substance found in the leaves of the coca plant, which has been used for centuries as a local anesthetic and stimulant. Illegal cocaine arrives in the USA either as a pure compound or as the hydrochloride salt(C7H21O4NHCl). At 25 degrees celsius, the salt is very soluble in water(2.59kg/L), but pure cocaine is much less so(1.70g/L) a. What is the maximum amount of salt in grams that can dissolve in 50.0mL of water? b. When a 25mL aqueous solution that contains 62.50 g of the salt is treated with NaOH, the salt is converted to pure cocaine. How much water in liters is needed additionally to dissolve the formed pure cocaine,Cocaine (C17H21O4N) is a natural substance found in the leaves of the coca plant, which has been used for centuries as a local anesthetic and stimulant. Illegal cocaine arrives in the USA either as a pure compound or as the hydrochloride salt (C17H21O4NHCl). At 25oC, the salt is very soluble in water (2.50 kg/L), but pure cocaine is much less so (1.70 g/L). What is the maximum amount of salt (in gram) that can dissolve in 50.0 mL of water? [1 mark.] When a 25 mL aqueous solution that contains 62.50 g of the salt is treated with NaOH, the salt is converted to pure cocaine. How much water (in liters) is needed additionally to dissolve the formed pure cocaine? Round your final answer off to two decimal points. C17H21O4NHCl(aq) + NaOH(aq) → C17H21O4N(aq) + H2O(l) + NaCl(aq)5.127 Photosynthesis produces glucose (C6H12O6) and oxygen from carbon dioxide and water:
- Cocaine (C₁₇H₂₁O₄N) is a natural substance found in cocaleaves, which have been used for centuries as a local anestheticand stimulant. Illegal cocaine arrives in the United States eitheras the pure compound or as the hydrochloride salt(C₁₇H₂₁O₄NHCl). At 25C, the salt is very soluble in water(2.50 kg/L), but cocaine is much less so (1.70 g/L). (a) Whatis the maximum amount (in g) of the salt that can dissolve in50.0 mL of water? (b) If the solution in part (a) is treated withNaOH, the salt is converted to cocaine. How much additionalwater (in L) is needed to dissolve it?a student carries out this chemical reaction in a beaker Zn+CuCl2 -> Cu+ZnCl2 after the reaction has come to completion, what should the student expect to find in the beaker ?Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) A. What is the %m/m of the solution? B. What is the molarity of the solution? C. What is the mole fraction of the solvent?
- A major component of honey is fructose (C6H12O6) with a molar mass of 180.16 g/mol. A tablespoon (15.0 mL) of honey is considered one serving. How many tablespoons must be eaten to consume 0.1900 moles of fructose? Assume honey is 100% fructose. The density of honey is 1.45 g/mL.What mass of KNO3 [MW=101] is needed to prepare 250.0mL of 0.450 M KNO3 in water?1.2048g sample of impure Na2CO3 is dissolved and allowed to react with a solution of CaCl2 resulting CaCO3 after precipitation, filtaration and drying was found to weight 1.0362g. calculate the percentage purity of Na2CO3
- A formula for compounding state qs ad 250 ml. This expression meansIf cobalt (II) sulfate is heated too strongly the following reaction will occur CoSO4 (s)-> Co(O) (s) +SO3(g) If you are heating a sample of CoSO4*6H2O and this reaction occurs along with dehydration, what will happen to the experimental percent water? Explain your answer.Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) A. What is the molarity of the solution? B. How many mL of the 2M palmitic acid stock solution will you need? Final answer must be rounded off to 2 decimal places, and shall NOT have any units.