Please solve this IR Spectrum(quid film)U4000wwwwwwww9898% of base peak30004391408013C NMR Spectrum(50.0 MHz, CDCI, solution)DEPT CH₂ CH, CHproton decoupledL200¹H NMR Spectrum(200 MHz, CDCI, solution)109817152000120V (cm¹)M134My1600160m/e7160200J12068000.0Mass Spectrum 0.51.0CgH1001.5628012002405solvent80problem 9UV spectrumsolvent: cyclohexane7.90 mg/10 mispath length:0.50 cm3004absorbance20034025023500 8 (ppm)TMSL08 (ppm)λ (nm)11

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Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter19: Nuclear Magnetic Resonance Spectroscopy

Section: Chapter Questions

Problem 19.36QAP: From the proton NMR spectrum in Figure 19-44, deduce the structure of this hydrocarbon

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Concept explainers

UV Visible Spectroscopy

Spectroscopy refers to the absorption or emission of light or other radiations by matter. When a substance or chemical absorbs light or radiation, they reach an excited state followed by de-excitation or emission of the light or radiation forming distinct spectra. UV-visible spectroscopy or ultraviolet-visible refers to the absorption and emission in the ultraviolet and visible regions of the electromagnetic spectrum.

Question

Please solve this

IR Spectrum
(quid film)
U
4000
wwwwwwww
9898
% of base peak
3000
43
91
40
80
13C NMR Spectrum
(50.0 MHz, CDCI, solution)
DEPT CH₂ CH, CH
proton decoupled
L
200
¹H NMR Spectrum
(200 MHz, CDCI, solution)
10
9
8
1715
2000
120
V (cm¹)
M
134
My
1600
160
m/e
7
160
200
J
120
6
800
0.0
Mass Spectrum 0.5
1.0
CgH100
1.56
280
1200
240
5
solvent
80
problem 9
UV spectrum
solvent: cyclohexane
7.90 mg/10 mis
path length:0.50 cm
300
4
absorbance
200
3
40
250
2
350
0 8 (ppm)
TMS
L
0
8 (ppm)
λ (nm)
1
1

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