Plot the stress-strain diagram and determine the following mechanical properties: (a) proportional limit; (b) modulus of elasticity; (c) yield point; (d) yield strength at 0.2% offset; (e) ultimate strength; and (f) rupture strength.
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- A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/L =1392 kips/in. What is the modulus of elasticity?The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
- A steel specimen of 300 mm length and 30 mm diameter is subjected to tensile test in a computerizedUTM. Under 54 kN of tensile load, the final length and diameter are observed as 300.112 mm and29.99634 mm respectively. Calculate (a) the Poission’s ratio and (b) the values of three moduli.The (G-E) diagram obtained in the tensile test performed on a metal sample with a diameter of 16 mm is as follows. The loads at points A, B and C and the elongation measured on l. 16 cm gauge length were determined as follows: B A B C Load (kgf) 4800 8400 7200 Elongation (mm) 0.192 28.8 38.4 c) Calculate the fracture work and the maximum elastic energy the metal rod can store. d) Find the cross-sectional area of a 6 m long rod made of this metal such that it can carry 12 tons of load with 2 times the safety of yield strength. How long does the rod extend under this load?1.5-7 The data shown in the table were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2 in.² in area and a gage length (the length over which the elongation is measured) of 2.000 inches. d. Estimate the value of the proportional limit. e. Use the 0.2% offset method to determine the yield stress. Load (kips) 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 ܩܙ ܘ 5.5 6.0 6.5 Elongation × 10³ (in.) 0 0.160 0.352 0.706 1.012 1.434 1.712 1.986 2.286 2.612 2.938 3.274 3.632 3.976 Load (kips) 7.0 7.5 8.0 8.5 9.0 9.5 10.0 10.5 11.0 11.5 12.0 12.5 13 Elongation × 10³ (in.) 4.386 4.640 4.988 5.432 5.862 6.362 7.304 8.072 9.044 11.310 14.120 20.044 29.106
- A tensile test was performed on a metal specimen with a diameter of 1⁄2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The data were plotted on a load-displacement graph, P vs. ∆L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P y∆L 5 1392 kips yin. What is the modulus of elasticity?2.7 The following readings were recorded during a tensile test of a mild steel specimen 24 mm wide by 10 mm thick and with a gauge length of 200 mm. Force (kN) 16 32 48 64 68 72 76 79 Elongation (mm) 0,066 0,133 0,198 0,264 0,281 0,304 0,355 1,125 Force (kN) 76,8 83,7 103,8 111 112,8 108 96 Elongation (mm) 3,75 6,66 15,00 25,00 36,5 45,0 50,0 The test piece fractured at a 50-mm elongation. Plot the load-extension dia- gram using the following scales: 10 divisions on the x-axis = 5-mm exten- sion; 10 divisions on the y-axis = 10 kN. On the same graph paper and using the scale 10 divisions on x-axis = 0,5-mm extension, and 10 divisions on y-axis = 10 kN, replot the elastic portion of the graph. Using the graphs, determine the (a) modulus of elasticity for mild steel; (b) yield stress; (c) ultimate tensile stress; and (d) percentage elongation.1. The following data were obtained during a tension test of an aluminum alloy. The initial diameter of the test specimen was 0.505 in., and the gage length was 2.0 in. Load ( Ib) Elongation (in.) Load ( Ib) Elongation (in.) 14000 0.020 2310 0.0022 14400 0.025 4640 0.0044 14 500 0.060 6950 0.0066 14600 0.080 9290 0.0088 14800 0.100 I1 600 0.0110 14600 0.120 13000 0.01 50 13600 Fracture Plot the stress-strain diagram and determine the following mechanical properties: a. proportional limit þ. modulus of elasticity S. vield stress at 0.2% offset d. ultimate stress e. nominal rupture stress.
- Calculate 6 Calculate the tensile stress when applied force of 120OON on specimen of * diameter of 7mm 111 O 211 O 311 O 411 OThe (G-E) diagram obtained in the tensile test performed on a metal sample with a diameter of 16 mm is as follows. The loads at points A, B and C and the elongation measured on l. 16 cm gauge length were determined as follows: B A B C Load (kgf) 4800 8400 7200 Elongation (mm) 0.192 28.8 38.4 a) Calculate the proportionality limit, modulus of elasticity, tensile strength, maximum uniform elongation, and contraction-elongation ratio of the metal. b) Since the measured diameter of the metal at break is 12 mm, find the constriction ratio and the actual stress at break.During a tensile test on a specimen the following results were obtainedload(KN) 15 30 40 50 55 60 65 70 75 80 82 80 70extension(mm) 0.05 0.094 0.127 0.157 1.778 2.79 3.81 5.08 7.62 12.7 16 19.05 22.9diameter of gauge length=19mmdiameter at fracture=16.49mmgauge length=100mmgauge lengthat fracture=121mmplot the complete load extension graph and the straight line portion to an enlarged scale .hence determinethe modulus of elasticitythe percentage elongationthe percentage reduction in areathe nominal stress at fracturethe actual stress at fracturethe tensile strength