7. The switch S, of Figure 7 has been opened for a long time and switch S, has been closed for a longtime. Switch S, is closed at t 0 sec and after 1 sec both switch S, and switch S, are openedsimultaneously and remain open indefinitely.(i) Find the mathematical expression for the inductor current i, through the inductor for all time.(ii) Plot the waveforms of current i, as functions of time.S2Aセ=1see8AS,t=i seewww-wwwwww0.8mオーo+10v2HFigure 7wwwwww

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Answered: Plot the waveforms of current ly as…

Plot the waveforms of current ly as funcuons of tine. Sz At=1 sec 8A S t=l see ww www www 0.8~ オーo +)10v 2H Figure 7 www www.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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From the given circuit. Switch S1 is in position A switch S2 is open. Both switches are in these states for a very long time. At t=0, switch S1 moves from position A to B while switch S2 remains open. 10ms after switch S1 moves to position B, switch S2 is closed and remains closed for 20ms only. ANSWER THE FOLLOWING: a.) Expression for the inductor current for 0 ≤ ? < 10??b.) Expression for the inductor current for 10?? ≤ ? < 30?? and 30?? ≤ ? < ∞c.) What is the time (in ms) after switch S1 moves to position B is the current in the inductor equivalent to 30% of the initial value (at ?=0).
calculate the time at which the 2 capacitor will have a equal charge. given that the 2 RC circuits (simple) composed of 2mF capacitor, 35kohms resistor, 12V of constant DC source. suppose that at t=0, 1 capacitor is discharged through resistor in its RC circuit (assuming that it is fully charged initially and the DC source is connected) while the other capacitor charged through DC source in its RC circuit through the resistor (assuming that it is uncharged initially).
Consider the given circuit. The switch has been closed for a very long time before opening at t=0s. Determine the capacitor voltage (in volts) right before the switch has been opened, the time constant of the circuit for t>0 (in ms), and the expression for the capacitor voltage for t≥0.
Given the circuit below with the switch closed for a long time, then opening at t=0, and with the values R1=129KΩ, R2=128KΩ, R3=103KΩ, calculate the time constant, τ, for the capacitor voltage solution for at t >0.
The circuit shown below is an underdamped system, and the current through the inductor has the form iL(t)=e^at ( ) (K1sinwt + K2coswt ) for t≥0 a. Determine the numerical values, including signs, of a and w b. If the initial conditions are iL(0) = 1A and Vc (0) =12V , determine the numerical values, including signs, of K1 and K2 c. Using the numbers determined above, write out the complete expression for iL(t)
a. Find the mathematical expressions for the transient behavior of thevoltage vC and the current iC if the capacitor was initially unchargedand the switch is thrown into position 1 at t = 0 s.b. Find the mathematical expressions for the voltage vC and the current iCif the switch is moved to position 2 at t = 3 ms.c. Find the mathematical expressions for the voltage vC and the current if theswitch is thrown into position 3 at t =5 ms.d. Plot the waveforms obtained in parts (a)–(c)
Consider the circuit. The switch has been closed for a long time before opening at t=0s. Give the expression for the capacitor current for t≥0 and the total dissipated energy (in μJ) in the 10KΩ resistor 5ms after the switch has been opened.
All capacitors were initially discharged. at t = 0, S1 is placed at position 1 and S2 is closed. During this phase, it has been determined that Eth and Rth seen by the equivalent capacitor are, respectively, 20 V and 6.0 kΩ. The time constant is 29 ms. At t = 15 ms, S1 is placed at position 2 and S2 is kept closed. Calculate the equivalent capacitor voltage vT at t = 15 ms. Enter your answer in V rounded to 2 decimal places. At t = 25 ms, S1 is kept at position 2 and S2 is opened. Data: R1 = 5 kΩ, R2 = 3 kΩ, R4 = 2 kΩ, R5 = 20 kΩ, R6 = 12.0 kΩ;
The current in and the voltage across a 5 H inductor are known to be zero for t≤0. The voltage across the inductor is given by the graph shown for t≥0. 1. Derive the expression for the current as a function of time in the intervals 0≤t≤1 s, 1 s≤t≤3 s, 3 s≤t≤5 s, 5 s≤t≤6 s, and 6 s≤t<∞. 2. For t>0, what is the current in the inductor when the voltage is zero? 3. Sketch i versus t for 0≤t<∞.
Electrical oscillations are initiated in a series circuit containing a capacitance C, inductance L, and resistance R. (a) If R <<√4L/C (weak damping), what time interval elapses before the amplitude of the current oscillation falls to 50.0% of its initial value? (b) Over what time interval does the energy decrease to 50.0% of its initial value?
A capacitor consists of two circular plates of radius a separated by a distance d(assume d << a). The centre of each plate is connected to the terminals of a voltagesource by a thin wire. A switch in the circuit is closed at time t = 0 and a current I(t) flows in the circuit. Thecharge on the plate is related to the current according to I (t) = dq/dt. We begin bycalculating the electric field between the plates. Throughout this problem you mayignore edge effects. We assume that the electric field is zero for r > a.(A) Use Gauss’ Law to find the electric field between the plates as a functionof time t, in terms of q(t), a, ε, and π. The vertical direction is the k direction. (B)Now take an imaginary flat disc of radius r < a inside the capacitor, as shownbelow. Using your expression for E above, calculate the electric flux through this flatdisc of radius r < a in the plane midway between the plates, in terms of r, q(t), a,and ε. (C)Calculate the Maxwell displacement…
IN THE CIRCUIT SHOWN, CONSIDER THAT V1=20 VDC, R1=1000 Ω, R2=3000 Ω, R3=3500 Ω AND C=1 mF.DETERMINE:A) THE TIME IT TAKES FOR THE CAPACITOR TO REACH ITS FINAL VALUE (5T), WHEN SWITCH 2 (INT 2) IS IN POSITION A AND SWITCH 1 (INT 1) IS CLOSED AT t=0,B) THE ENERGY STORED BY THE CAPACITOR ONCE IT HAS BEEN FULLY CHARGED WITH THE SAME POSITION OF SWITCHES AS ITEM A)C) ONCE THE CAPACITOR HAS BEEN FULLY CHARGED WITH SWITCH 1 CLOSED, SWITCH 2 MOVES POSITION (GOES TO B) AT A NEW t=0. NOW DETERMINE THE VALUE OF THE VOLTAGE ON THE CAPACITOR AT t=3.5 SECONDS