Please help with question 1 DATA TABLEMass of test tubeMass of test tube & metalMass of metalMass of calorimeterMass of calorimeter & waterMass of waterTemp of boiling water (metal)Temperature of water in foam cupHighest temp (after metal added)Change in water temperature(ATW)Change in metal temperature(ATM)Trial 119.34g38.14g18.8g3.81951.70947.99206°F 98°C72.5°F 23°C80 of26°C3°C-72°CTrial 219.20g37.95g18.75g4.26949.30g45.04g१८०८72.5° 23°C27%4°C-69⁰cPost-lab Calculations:1. Calculate the specific heat, for both trials, by setting heat gained by the water(qw) to heat lost by the metal (qm).Trial 1:Trial 2:Average specific heat of the trials:2. Calculate your percent error with the accepted value for the specific heatbeing of 0.5024J/g°C.

The question is based on the concept of calorimetry. whatever heat released by metal is absorbed by…

Answered: Post-lab Calculations: 1. Calculate the…

Post-lab Calculations: 1. Calculate the specific heat, for both trials, by setting heat gained by the water (qw) to heat lost by the metal (qm). Trial 1: Trial 2:

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter12: Thermodynamic Processes And Thermochemistry

Section: Chapter Questions

Problem 70AP

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Question

Please help with question 1

DATA TABLE
Mass of test tube
Mass of test tube & metal
Mass of metal
Mass of calorimeter
Mass of calorimeter & water
Mass of water
Temp of boiling water (metal)
Temperature of water in foam cup
Highest temp (after metal added)
Change in water temperature
(ATW)
Change in metal temperature
(ATM)
Trial 1
19.34g
38.14g
18.8g
3.819
51.709
47.99
206°F 98°C
72.5°F 23°C
80 of
26°C
3°C
-72°C
Trial 2
19.20g
37.95g
18.75g
4.269
49.30g
45.04g
१८०८
72.5° 23°C
27%
4°C
-69⁰c
Post-lab Calculations:
1. Calculate the specific heat, for both trials, by setting heat gained by the water
(qw) to heat lost by the metal (qm).
Trial 1:
Trial 2:
Average specific heat of the trials:
2. Calculate your percent error with the accepted value for the specific heat
being of 0.5024J/g°C.

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