-pound weight stretches a spring 2 feet. The weight is released from rest 20 inches above the equilibrium position, and the resulting motion takes place in a medium offering a dampi to gravity.) nmplete the Laplace transform of the differential equation. 1)s. sx{x} + [ the Laplace transform to find the equation of motion x(e). ]+()*(x) = 0

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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A 4-pound weight stretches a spring 2 feet. The weight is released from rest 20 inches above the equilibrium position, and the resulting motion takes place in a medium offering a damping force numerically equal to times the instantaneous velocity. (Use g = 32 ft/s² for the acceleration
due to gravity.)
Complete the Laplace transform of the differential equation.
s²x{x} + ([
])s£{x} +
Use the Laplace transform to find the equation of motion x(t).
x(t) =
])L{x} = 0
Transcribed Image Text:8 A 4-pound weight stretches a spring 2 feet. The weight is released from rest 20 inches above the equilibrium position, and the resulting motion takes place in a medium offering a damping force numerically equal to times the instantaneous velocity. (Use g = 32 ft/s² for the acceleration due to gravity.) Complete the Laplace transform of the differential equation. s²x{x} + ([ ])s£{x} + Use the Laplace transform to find the equation of motion x(t). x(t) = ])L{x} = 0
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