Predict the number of H-NMR resonance for the following molecules: 1. 1,2-dichloro-anthracene 2. 2,3-dichloro-anthracene 3. 1,5-dichloro-anthracene 4. 1,4,5,8-tetrachloro-anthracene The numbering scheme for the anthracene molecule is give below: 8. 9. 8a 9a 6. 3 10a 4a 5 10 4
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- Compounds A and B are isomers having the molecular formula C4H8O3. Identify A and B on the basis of their 1H NMR spectra.Compound A: δ 1.3 (3H, triplet); 3.6 (2H, quartet); 4.1 (2H, singlet); 11.1 (1H, broad singlet)Compound B: δ 2.6 (2H, triplet); 3.4 (3H, singlet); 3.7 (2H triplet); 11.3 (1H, broad singlet)How could 1H NMR spectroscopy be used to distinguish among isomers A, B, and C?1) Propose the structures for the following 1H and 13C NMR spectra. a) Molecular Formula: C5H10O2 1H-NMR, CDCl3 Solvent, Molecular Formula: C5H10O2 13C-NMR, CDCl3 Solvent, Molecular Formula: C5H10O2 in the pictures
- Four isomers A-D with the formula C5H12O exhibit different reactivity patterns as indicated below. Isomer A reacts with PCC and CrO3 to provide identical products. Isomer B reacts with PCC and CrO3 to provide different products. Isomers C and D do not react with either PCC or CrO3. Isomers A, B, and C readily react with NaH but D does not show any reactivity with NaH. The 1H NMR splitting patterns for these isomers are as follows. Isomer A: δ 0.91 (d, 3H), 0.90 (d, 3H), 1.18 (d, 3H), 1.92 (dqq, 1H), 3.38 (dq, 1H), 3.58 (bs, 1H). Isomer B: δ 1.25 (s, 9H), 3.45 (s, 2H), 3.65 (bs, 1H). Isomer C: δ 0.90 (t, 3H), 1.44 (q, 2H), 1.24 (s, 6H), 3.65 (bs, 1H). Isomer D: δ 1.10 (t, 3H), 1.13 (d, 6H), 3.19 (septet, 1H), 3.50 (q, 2H). Based on all of this information, provide the structures of A-D. (Note: If there is a chiral center on any of these molecules, assume the stereochemistry as “R”. dqq=doublet of a quartet of a quartet, bs=broad singlet)When 2-bromo-3,3-dimethylbutane is treated with K+ −OC(CH3)3, a singleproduct T having molecular formula C6H12 is formed. When 3,3-dimethylbutan-2-ol is treated with H2SO4, the major product U has thesame molecular formula. Given the following 1H NMR data, what are thestructures of T and U? Explain in detail the splitting patterns observedfor the three split signals in T.1H NMR of T: 1.01 (singlet, 9 H), 4.82 (doublet of doublets, 1 H, J = 10, 1.7 Hz), 4.93 (doublet of doublets, 1 H, J = 18, 1.7 Hz), and 5.83 (doublet ofdoublets, 1 H, J = 18, 10 Hz) ppm1H NMR of U: 1.60 (singlet) ppm Additional problems on the spectroscopy of alkenes are given in Chapters A–C:Mass spectrometry: A.16b, A.20, A.23Infrared spectroscopy: B.5, B.7(A), B.12c, B17a, B.18cNuclear magnetic resonance spectroscopy: C.12a; C.15d, e; C.29d; C.32d;C.37; C.38d, f; C.43i, j; C.44; C.45; C.49d, f; C.50b; C.51c; C.55A and B, isomers of molecular formula C3H5Cl3, are formed by the radical chlorination of a dihalide C of molecular formula C3H6Cl2.a. Identify the structures of A and B from the following 1H NMR data:Compound A: singlet at 2.23 and singlet at 4.04 ppmCompound B: doublet at 1.69, multiplet at 4.34, and doublet at 5.85 ppmb. What is the structure of C?
- When 2-bromo-3,3-dimethylbutane is treated with K+ -OC(CH3)3, a single product T having molecular formula C6H12 is formed. When 3,3-dimethylbutan-2-ol is treated with H2SO4, the major product U has the same molecular formula. Given the following 1H NMR data, what are the structures of T and U? Explain in detail the splitting patterns observed for the three split signals in T.1H NMR of T: 1.01 (singlet, 9 H), 4.82 (doublet of doublets, 1 H, J = 10, 1.7 Hz), 4.93 (doublet of doublets, 1 H, J = 18, 1.7 Hz),and 5.83 (doublet of doublets, 1 H, J = 18, 10 Hz) ppm1H NMR of U: 1.60 (singlet) ppmYou have a sample of a compound of molecular formula C11H15NO2, which has a benzene ring substituted by two groups, (CH3)2N− and −CO2CH2CH3, and exhibits the given 13C NMR. What disubstituted benzene isomer corresponds to these 13C data?You have a sample of a compound of molecular formula C11H15NO2, which has a benzene ring substituted by two groups, (CH3)2N – and – CO2CH2CH3, and exhibits the given 13C NMR. What disubstituted benzene isomer corresponds to these 13C data?
- Part 3B Set 1. Can 1H NMR spectroscopy be used to differentiate between the two compounds? Briefly explain why or why not. Predict the 1H NMR spectrum for each compound (include integration, multiplicity, and approximate chemical shift). Either draw the actual spectrum or put in a data table format.A2 what is the NMR spectrum of benzylcyclohexan-1-ol. explain in detail how to expect to see the nmr spectra and tell about shift, area and splitDraw the structure of the compound that produced the spectra below. The infrared spectrum has strong bands at 1720 and 1738 cm-1.