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- Based on a large sample of capacitors of a certain type, a 95% confidence interval for the mean capacitance, in μF, was computed to be (0.213, 0.241). Find a 90% confidence interval for the mean capacitance of this type of capacitor.The article for helmet impact assessment reports that when each soccer helmet in a random sample of 37 suspension-type helmets was subjected to an impact test, 24 showed damage. Let p be the proportion of all such helmets that would show damage when tested in the prescribed manner.a) Calculate a 99% confidence interval for p.b) What sample size would be required for the 1-sided width of a 99% confidence interval to be at most 0.05, regardless of Pˆ ? Note:The exercise in the image is in Spanish, to make the exercise more understandable.A random sample of 20 bundles of wool fibers had a sample mean of x =436.5 and a sample standard deviation of s =11.90 in terms of breaking strength. Construct a two-sided 95% confidence interval for the average breaking strength ?.
- A random sample of 425 JAC students found that the average number of caffeinated drinksconsumed per day was 2.8 with s=0.3. a. Calculate a 95% confidence interval. b. Interpret.A fish hatchery manager estimates that on average fisherpersons catch 3.5 fisheach fishing trip. A random sample of 10 fisherpersons showed they caught 3.9 fishper trip, with a standard deviation of 1.7 fish per trip. Perform a test of hypothesisat a 0 .10 alpha level to determine whether or not her claim is true. Use a two tailedtest of hypothesis and the critical value method.A study of 420 comma 026 cell phone users found that 140 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be 0.0434 % for those not using cell phones. Complete parts (a) and (b). a. Use the sample data to construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. b. Do cell phone users appear to have a rate of cancer of the brain or nervous system that is different from the rate of such cancer among those not using cell phones? Why or why not?
- A sample of 51 recent graduates from a specific program yielded an average starting salary of $38,500 and a standard deviation of $2563. (a) Find the 95% confidence interval for the standard deviation in starting salary based on this sample. (b) Interpret the confidence interval for part (a) in the context of this problemConstruct a 95% confidence interval for the mean difference in their total ventilation when the subjectsare at rest and when performing imaginary muscular work if hypnosis is induced between the twophases.Do not use R.In a survey funded by the UW school of medicine, 750 of 1000 adult Seattle residents said they did not believe they could come down with a sexually transmitted infection (STI). Construct a 95% confidence interval estimage of the proportion of adult Seattle residents who don't believe they can contract an STI. (Use a zz score of 1.96 for your computations.)
- A random sample of 12 female students in a certaindormitory showed an average weekly expenditure of $8.00for snack foods, with a standard deviation of $1.75. Constructa 90% confidence interval for the average amount spent eachweek on snack foods by female students living in thisdormitory, assuming the expenditures to be approximatelynormally distributed.From a research survey, it was found that a random sample of 18 elementary graduates of an exclusive private school has a mean NEAT score of 90 with a standard deviation of 16, while a random sample of 24 elementary graduates of a public school showed a mean NEAT score of 85 with a standard deviation of 12. Is there a significant difference in the NEAT performance of these two groups of elementary graduates? a. Use the traditional method, and b. The P-value method c. Construct a 95% confidence interval for the difference in mean.In a survey of 2,472 adults, 1,949 reported that e-mails are easy to misinterpret, but only 1,281 reported that telephone conversations are easy to misinterpret. Complete parts (a) through (c) below. b. Construct a 95% confidence interval estimate for the population proportion of adults who report that telephone conversations are easy to misinterpret. ____≤π≤____ (Round to four decimal places as needed.)