Problem 1: In the ray diagram shown below (angles not to scale), the ray is incident a the critical angle on the interface between materials 2 and 3. Angle = 60.0°, and two of the indexes of refraction are n₁ = 1.70 and n₂ = 1.60. (a). What is the index of refraction n3? (b). What is the angle 0? (c). If decreased, does light refract into material 3? N2 nz n1
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- Consider a ray of light that propagates from air ( n=1 ) to any one of the materials listed below. Assuming that the ray strikes the interface with any of the listed materials always at the same angle θ1 , in which material will the direction of propagation of the ray change the most due to refraction? What is the critical angle θcrit for light propagating from a material with index of refraction of 1.50 to a material with index of refraction of 1.00?In the figure, light enters a 90° triangular prism at point A with incident angle θ, and then some of it refracts at point B with an angle of refraction of 90°. (a) What is the index of refraction of the prism in terms of θ? (b) What, numerically, is the maximum value that the index of refraction can have? (c) Does light emerge at B if the incident angle at A is (i) increased slightly and (ii) decreased slightly? Hint: sin2θ + cos2θ = 1. Answer: √(1+ sin2θ), 1.41, emerges into air, internally reflectedA light ray entering an optical fiber made from crown glass and surrounded by air is first refracted and then reflected as shown in the figure above. Enter, in internal notation, using the appropriate brackets and without spaces, the set of incident angles theta 1 for which the fiber undergoes total internal reflection.
- Determine the image distance ?i for an object ?o=5.100 cm from a diverging lens with radius of curvature ?=4.080 cm and index of refraction 1.800. Express your answer as a positive quantity. |?i|= What is the magnification ? of the object? Be sure to insert the proper sign if needed. ?= What is the nature of the image? inverted and smaller upright and smaller inverted and larger upright and largerYou can determine the index of refraction of a substance by determining its critical angle. (a) What is the index of refraction of a substance that has a critical angle of 68.4° when submerged in water? What Is the substance, based on Table 1.1? (b) What would the critical angle be for this substance in air?When a light ray crosses from water into glass, it emerges at an angle of 30° with respect to the normal of the interface. What is its angle of incidence? I used Snell's Law to find the angle of incidence as 34.8 degrees (rounded to 3 sig fig), using index of refraction for water as 1.333 and for glass as 1.52. However, the answer was marked as wrong. Could you please explain steps for solving to get theta as approximately 42 degrees?
- Although we do not prove it here, the minimum angle of deviation δmin for a prism occurs when the angle of incidence θ1 is such that the refracted ray inside the prism makes the same angle with the normal to the two prism faces1 as shown. Obtain an expression for the index of refraction of the prism material in terms of the minimum angle of deviation and the apex angle Φ.Determine the image distance ?idi for an object ?o=7.000 cm from a diverging lens with radius of curvature ?=5.600 cm and index of refraction 1.800. Express your answer as a positive quantity. b) What is the magnification ?m of the object? Be sure to insert the proper sign if needed. c) What is the nature of the image?An underwater scuba diver sees the Sun at an apparent angle of 46.0° above the horizontal. What is the actual elevation angle of the Sun above the horizontal? (Use 1.333 for the index of refraction of water.)
- A block of acrylic has a wedge-shaped cavity filled with air, where the opening angle θ is 38°. If a light ray travelling straight up is incident from the cavity into the block as shown in the figure, what angle does the refracted light ray make with the indicated normal? Enter -1 if the light ray does not exit the cavity at the indiciated point because of total internal reflection.The index of refraction. Od one medium is n(low)=1.6 & the index of refraction of an adjoining (neighbouring) medium is n(high)=2.5. Total internal reflection of light is found to occur at the boundary of these two mediums. What is the critical angle of this system at which total internal reflection occurs? Did total internal reflection go occur, should the incident angle be larger or smaller than this value? Or can it only be exactly at this angle? Within which medium must the light originate for total internal reflection to occur? AKA within which medium cab the incident light be totally internally reflected & not transmitted? -n(high) -n(low) -it doesn’t matter -not enough infoPart A: In the above figure, a light beam shines through air and then strikes a mirror, making an angle theta = 23.2 degrees with respect to the vertical, as shown. The reflected beam then strikes a pane of glass of thickness h = 1.32 cm, located a distance y= 57.6 cm from the mirror, and then exits the glass pane at the bottom, a horizontal distance x cm away from where it struck the mirror. What is the value of x? Part B: This time, the incident ray is coming in from water (n=1.33) rather than air. And this time, theta = 37.5 degrees, y = 27.1 cm and h = 1.34 cm. What is x now? PLEASE ANSWER BOTH PARTS.