Problem 2: A proton moving at 2.00x106 m/s enters a region of magnetic field with B = 5.00T that is perpendicular to the motion. What is the radius of the resulting circular orbit? mp = 1.67x10-27 kg and e = 1.60x10-1⁹ C.

Classical Dynamics of Particles and Systems
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ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter14: Special Theory Of Relativity
Section: Chapter Questions
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What is the radius of the resulting circular orbit?

Problem 2: A proton moving at 2.00x106 m/s enters a region of magnetic
field with B = 5.00T that is perpendicular to the motion. What is the
radius of the resulting circular orbit? mp = 1.67x10-27 kg and e =
1.60x10-1⁹ C.
Transcribed Image Text:Problem 2: A proton moving at 2.00x106 m/s enters a region of magnetic field with B = 5.00T that is perpendicular to the motion. What is the radius of the resulting circular orbit? mp = 1.67x10-27 kg and e = 1.60x10-1⁹ C.
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