Problem 2: According to the Loselt! Mobile App, you will get 140 calories from a serving of vanilla yogurt. Consumer Reports tested 14 brands of vanilla yogurt and found that the average calories per serving was 158 calories with a standard deviation of 44.7 calories, with a distribution that was approximately unimodal and symmetric. A. Create and interpret a 95% confidence interval for the average calorie content of vanilla yogurt. (State your conditions for inference.) B. Based on your confidence interval, is there evidence that the Consumer Reports test is different than what Loselt! Mobile App claims? Explain.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter4: Equations Of Linear Functions
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Problems a and b please 

Problem 2: According to the Loselt! Mobile App, you will get 140 calories from a serving of
vanilla yogurt. Consumer Reports tested 14 brands of vanilla yogurt and found that the average
calories per serving was 158 calories with a standard deviation of 44.7 calories, with a
distribution that was approximately unimodal and symmetric.
A. Create and interpret a 95% confidence interval for the average calorie content of vanilla
yogurt. (State your conditions for inference.)
B. Based on your confidence interval, is there evidence that the Consumer Reports test is
different than what Loselt! Mobile App claims? Explain.
Transcribed Image Text:Problem 2: According to the Loselt! Mobile App, you will get 140 calories from a serving of vanilla yogurt. Consumer Reports tested 14 brands of vanilla yogurt and found that the average calories per serving was 158 calories with a standard deviation of 44.7 calories, with a distribution that was approximately unimodal and symmetric. A. Create and interpret a 95% confidence interval for the average calorie content of vanilla yogurt. (State your conditions for inference.) B. Based on your confidence interval, is there evidence that the Consumer Reports test is different than what Loselt! Mobile App claims? Explain.
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