Problem 2 For the system shown calculate the short-circuit MVA at A and at B. 20 kVA 10% 30 kVA 5% 115 kV (3+ j12)2 To load 10KVA 7% G2 ulu m
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A: According to question answer rule of Bartleby I have to solve first three sub part.
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A: NOTE: We’ll answer the first question since the exact one wasn’t specified. Please submit a new…
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A: The Correct solution can be achieved as follows.
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A: The power system solution is given below.
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Q: A- Consider the system shown below. Phase b is open due to conductor break. Calculate the sequence…
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Q: 5. A 3-phase overhead transmission line has the following constants : Resistance/phase Inductive…
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- a) Draw the sequence network and calculate the sub-transient fault current for a dead short circuit on one phase to ground at bus 4 with fault impedance j1.78 p.u for the system shown in Fig. The system data's are Machine 1: Xd”=j0.21p.u , X2=j0.4p.u; X0= j0.55p.u ; Machine 2: Xd”=j0.21p.u , X2=j0.4p.u; X0= j0.55p.u ; Transformers T1 and T2 : X1=X2=X0= j1.2p.u The transmission line reactance X1=X2= j0.21p.u and X0=0.97 p.u.A balanced load with ZR = ZB = ZY = ……<00 Ω was supplied a three phase 50 Hz, 100 V between line (balanced source). A fault on phase ‘B’ causes an open circuit, which unbalanced the load as shown in Figure 4. Similarly, a fault on the load of phase ‘Y’ cause a short-circuit, which unbalanced the load as shown in Figure 5. Using complex notation determine and analyse the individual phase currents and the neutral current in both figure.Q: For the following OLD, take Sg = 50 MVA and VB = 22 kV at thetransmission line to find the short circuit current if a 3-ph fault occurs atthe middle of transmission line.15 MVA20 MVAX = j0.6 pu(15:35) kVG-EX = j0.3 pu25 MVA(40:15) kV15 MVA(6+j8) Q23 kVM18 kVT.LX = j0.5 puT1T2´x = j0.3 pu
- The 60 mile, 115 kV line GH (Figure P12.8) is operating with the voltages ateach end 30° out of phase when a three-phase fault occurs at 80% of the distance from bus G. This fault has 12 Ω arc resistance. The currents flowing tothe fault are as shown and are in per unit at 100 MVA, 115 kV.d. Determine if the zone 1 mho unit at H set for 90% of the line GH can operate for this fault. Assume that the angle of the mho characteristic is 75°.e. Describe how this three-phase fault can be cleared by the line distance relays.Q5: A SL-G fault occurs on the low voltage side of a transformer that connects a motor to a generator at generating plant. The rated values for each element are:M: 0.6 kV, 5 MVA, X1 = X2 = 20%, X0 = 4%, grounded through 2% reactance.T: 3-single phase units, each is: (2400 Grounded Y: 600 Δ) V, 2.5 MVA, Xt = 10%.G: 4.16 kV, 7.5 MVA, X1 = X2 = 10%, X0 = 5%, grounded through 5% reactance.Draw the sequences networks and determine the fault current in Amperes. (Take the generator ratings as a base).In the shown below power system, both generators G1 and G2 emf’s are equal.All the system data are shown on the system diagram.a) Draw the system diagram in per unit using (MVA)base = 75 and (KV)base =20 KV in the generators side.b) Calculate the three-phase balanced short circuit current (If) at busbar 3 inAmpere and the fault level (MVA)sc in MVA.c) If the fault at busbar 3 is a line-to-line fault, calculate the fault current inAmpere and the fault level (MVA)sc in MVA.
- In a short circuit test on 132 kV, 3-phase system, the breaker gives the following results: Power factor of the fault = 0.45. Recovery voltage 0.9 time of full line voltage. The breaking current is symmetrical. The restriking transient has a natural frequency of 15 kHz. Calculate the rate of rise of restriking voltage (RRRV) in the following types of faults: (1) Grounded fault (2) Undergrounded fault.The one line diagram of a three phase power system is as shown in Figure 7 Impedances are marked in per unit on a 100 MVA, 400 kV base The load at bus 2 is S2 15.93 MW - j 33.4 MVar, and at bus 3 is S3 77 MW + j 14 MVar It is required to hold the voltage at bus 3 at 400 kV Working in per unit, determine the voltage at buses 2 and 1A balanced three-phase source with grounded neutral has line-to-neutral voltages of 120 volts with an-bn-cn sequence. This source has an internal series impedance of 0.15+j2.0 ohms per phase. It supplies power to an unbalanced three-phase delta load with impedances: Zab = 30+j40; Zbc = 50-j40; Zca = 65+j25 ohms. If there is a double-line-to-ground fault at lines b and c load-side, what is the magnitude of the fault current injected to the ground in amperes?
- A 25 MVA, II kV generator has X"d=0.2 p.u. X2 = 0.3p.u. and X0=0.1 p.u. Tht neutral of generator is solidly grounded. Determine the subtransient current in the generator and the line to line voltages for subtransient condition when a Y-B-G fault occurs at the generator terminals. Assume prefault currents and fault resistance to be zero.Line impedances for the power system shown in Figure 1 are Z12 = Z23 = 3.0 + j40.0 Ω, and Z24 = 6.0 + j80.0 Ω. Reach for the zone 3 B12 impedance relays is set for 100% of line 1–2 plus 120% of line 2–4. (a) For a bolted three-phase fault at bus 4, show that the apparent primary impedance “seen” by the B12 relays is Zapparent = Z12 + Z24 + (I32/I12)Z24 where (I32/I12) is the line 2–3 to line 1–2 fault current ratio. (b) If |I32/I12| > 0.20, does the B12 relay see the fault at bus 4?A synchronous generator is feeding its rated power of 250 MW to a large 60 Hz network over a double circuit transmission The maximum steady state power that can be transmitted over the line with both circuits in service is 500 MW and is 350 MW with any one out of service. A solid three-phase fault occurring at the network-end of one of the lines causes it to trip. If inertia constant is H = 3.5 s, calculate the critical clearing angle and critical clearing time in which the circuit breakers must trip so that synchronism is preserved.